can you describe the code below
function [Y] = mu_law_expander(Xq,u)
for n = 1:numel(Xq)
disp(n);
Y(n) = ((-1 + (1+u)^abs(Xq(n))) / u) * sign(Xq(n));
end
%%

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madhan ravi
madhan ravi 2018년 10월 18일
편집: madhan ravi 2018년 10월 18일

0 개 추천

Xq is a vector , u is a scalar
the loop runs from 1 to the number of elements of Xq
number of iteration is displayed which is n here
and then the value is calculated according to the given formula
abs() considers Xq value as positive even if the value is negative and sign() returns 1 if the value is greater than zero and zero otherwise are matlab's inbuilt function
that's it

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madhan ravi
madhan ravi 2018년 10월 18일
if something is not clear let know else accept the answer

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2018년 10월 18일

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