viewSolid is not working

조회 수: 4 (최근 30일)
Ravi Prakash
Ravi Prakash 2018년 10월 14일
댓글: Steven Lord 2025년 9월 18일
Its not working in my Matlab app.Its showing invalid function.What can i do

답변 (2개)

Walter Roberson
Walter Roberson 2018년 10월 14일
  댓글 수: 2
Tansheed
Tansheed 2023년 12월 21일
I did download it and moved it into the same file with the matlab files just as my lecturer instructed me to do. But it still shows invalid to me but in my peers comupters it succesfully executes the action
Tansheed
Tansheed 2023년 12월 21일
Please tell us the possible reasons and how to slove them

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ATHUL N
ATHUL N 2025년 9월 18일
clc;
clear all;
syms x y z
value = int(int(6*x*y, z, 0, 1 + x + y), y, 0, sqrt(x),x,0,1
Error using sym/int (line 128)
Too many arguments.
viewSolid(z,0,1+x+y,y,0*x,sqrt(x),x,0,1);
  댓글 수: 1
Steven Lord
Steven Lord 2025년 9월 18일
This line of code (commented out so I can run other commands later in the comment) is not syntactically valid, as it has three ( and two ). I assume you ran it and then deleted one of the closing parentheses. Where was that closing parenthesis? Was it at the end of the line?
%{
value = int(int(6*x*y, z, 0, 1 + x + y), y, 0, sqrt(x),x,0,1
%}
If it was, the inner call to int looks fine. [Since z doesn't appear in 6*x*y, you're integrating a constant.]
syms x y z
innerIntegral = int(6*x*y, z, 0, 1 + x + y)
innerIntegral = 
If you're trying to perform a triple integral, the innermost one over z, the middle one over y, and the outermost over x, you're missing two closing parentheses and an extra int( call.
middleIntegral = int(innerIntegral, y, 0, sqrt(x))
middleIntegral = 
outerIntegral = int(middleIntegral, x, 0, 1)
outerIntegral = 
Or putting them all together in one line:
% Added vvvv v v
value = int(int(int(6*x*y, z, 0, 1 + x + y), y, 0, sqrt(x)),x,0,1)
value = 

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