Put a given sequence on time slots

For example, I have 48-time slots (t) and I want to put a block of a sequence [1,1,0,0] on these time slots randomly from (t+n) to (t+n+4). How can i generate such a sequence.

Answer 1

[Walter Roberson]

n = randi(length(t) - 3)
t(n:n+3) = [1 1 0 0]

[Daud]

Thank you very much for the reply>

I could not understand the above code:

Well for example:

d = [1 1 0 0];

m = zeros(12,1); 

for t = 1:length(d):12

       m(t:t+length(d)-1) = d;

end

I will get [110011001100]

But I want this sequence in random means:

e.g

It might be [011000011000] or [001100110000] e.t.c.

note: I have a fixed block "d" but I want to activate this "d" on random time slot "t".

[Walter Roberson]

You did not follow my instructions to use randi. Also, you appear to be wanting to put in multiple copies of the block.

The below code puts in a configurable number of copies of d.

This code makes no attempt to backtrack if it gets stuck, so in theory it could get stuck after placing as few as 7 copies of length 4 into your array of length 48, such as an occupancy pattern of

000111100011110001111000111100011110001111001111

I assume in this code that it is not permitted to overlap even in places where d is 0 -- so, for example, that it is not permitted to generate 1101100 even though after dropping in the first 1100 that the 4th position is 0: I deem that anything initialized with a value from d cannot be written to again.

m = zeros(1, 48);
d = [1 1 0 0];
num_copies = 3;   %put d into m this many times

used = false(size(m));
Ld = length(d);

for K = 1 : num_copies
  while true
    n = randi(length(m) - Ld + 1);
    if ~any(used(n:n+Ld-1)); break; end
  end
  m(n : n + Ld - 1) = d;
  used(n : n + Ld - 1) = true;
end

[Hiba Haider]

hello dear

same idea i have 24 slot for example i want choose one slot from slot 11 to slot 22 how can i apply

[Walter Roberson]

@Hiba Haider

randi([11 22])