How to speed up the program?

조회 수: 3 (최근 30일)
Henan Fang
Henan Fang 2018년 9월 28일
편집: Stephen23 2018년 9월 28일
(x,y) is a function generated as the following codes. I need to calculate the integration that "integral2(@(X,Y) arrayfun(@(x,y) Tuu(x,y),X,Y),0.01,pi/2,0,pi/4)". However, the program is too slow to use. How to speed up this program in details? Many thanks! The codes of Tuu(x,y) are as following:
function U=Tuu(x,y)
syms kz d
m = 2;
dd=2.106*(m+1);
vh = 4;
mu = 11;
delta = 8;
HBAR = 1.05457266e-34;
ME = 9.1093897e-31;
ELEC = 1.60217733e-19;
Kh = 2.106;
vKh = [0,0,0;Kh,0,0;-Kh,0,0;0,Kh,0;0,-Kh,0];
kc = sqrt(2.*ME.*ELEC/HBAR^2).*1e-10;
ku = kc.*sqrt(mu+delta);
kd = kc.*sqrt(mu-delta);
a3 = [pi/Kh,pi/Kh,sqrt(2).*pi/Kh];
kuu =[-ku.*sin(x).*cos(y), -ku.*sin(x).*sin(y), kz];
n=0:m;
for p=1:5;
for q=1:5;
tuu(p,q)= (sum((kuu + vKh(p,:)).^2)-ku^2).*(p==q)+ kc^2*vh*sum(exp(i.*n.*sum((vKh(q,:)-vKh(p,:)).*a3)))/(m+1).*(p~=q);
end
end
dtuu=det(tuu);
kz0=vpasolve(dtuu,kz);
kzz=kz0(real(vpa(kz0))>=0&imag(vpa(kz0))>=0);
tuu1=subs(tuu,kz,kzz(1));
tuu2=subs(tuu,kz,kzz(2));
tuu3=subs(tuu,kz,kzz(3));
tuu4=subs(tuu,kz,kzz(4));
tuu5=subs(tuu,kz,kzz(5));
tuu11=double(tuu1);
tuu22=double(tuu2);
tuu33=double(tuu3);
tuu44=double(tuu4);
tuu55=double(tuu5);
nuu1=null(tuu11);
nuu2=null(tuu22);
nuu3=null(tuu33);
nuu4=null(tuu44);
nuu5=null(tuu55);
piuu=[nuu1,nuu2,nuu3,nuu4,nuu5];
pei=[1;0;0;0;0];
A=piuu\pei;
psiuu1=A(1).*nuu1(1)*exp(i*kzz(1)*d)+A(2)*nuu2(1)*exp(i*kzz(2)*d)+A(3)*nuu3(1)*exp(i*kzz(3)*d)+A(4)*nuu4(1)*exp(i*kzz(4)*d)+A(5)*nuu5(1)*exp(i*kzz(5)*d);
psiuu2=A(1).*nuu1(2)*exp(i*kzz(1)*d)+A(2)*nuu2(2)*exp(i*kzz(2)*d)+A(3)*nuu3(2)*exp(i*kzz(3)*d)+A(4)*nuu4(2)*exp(i*kzz(4)*d)+A(5)*nuu5(2)*exp(i*kzz(5)*d);
psiuu3=A(1).*nuu1(3)*exp(i*kzz(1)*d)+A(2)*nuu2(3)*exp(i*kzz(2)*d)+A(3)*nuu3(3)*exp(i*kzz(3)*d)+A(4)*nuu4(3)*exp(i*kzz(4)*d)+A(5)*nuu5(3)*exp(i*kzz(5)*d);
psiuu4=A(1).*nuu1(4)*exp(i*kzz(1)*d)+A(2)*nuu2(4)*exp(i*kzz(2)*d)+A(3)*nuu3(4)*exp(i*kzz(3)*d)+A(4)*nuu4(4)*exp(i*kzz(4)*d)+A(5)*nuu5(4)*exp(i*kzz(5)*d);
psiuu5=A(1).*nuu1(5)*exp(i*kzz(1)*d)+A(2)*nuu2(5)*exp(i*kzz(2)*d)+A(3)*nuu3(5)*exp(i*kzz(3)*d)+A(4)*nuu4(5)*exp(i*kzz(4)*d)+A(5)*nuu5(5)*exp(i*kzz(5)*d);
Tuux=ku.*sin(x).*(imag(conj(psiuu1)*diff(psiuu1,d)+conj(psiuu2)*diff(psiuu2,d)+conj(psiuu3)*diff(psiuu3,d)+conj(psiuu4)*diff(psiuu4,d)+conj(psiuu5)*diff(psiuu5,d)));
U=double(subs(Tuux,d,dd));
end
  댓글 수: 3
Henan Fang
Henan Fang 2018년 9월 28일
@Stephen Cobeldick Can you tell me, in detail, how to perform numeric calculations instead of symbolic ones in this program?
Stephen23
Stephen23 2018년 9월 28일
편집: Stephen23 2018년 9월 28일
"Can you tell me, in detail, how to perform numeric calculations instead of symbolic ones in this program?"
Not really, as that function contains no code comments, no help, no links, no references, no examples, no demo, no explanation what it is doing. But it is possible that you could replace symbolic operations with faster numeric operations, if you want a numeric result at the end.
If you ask the author of that function they should be able to describe what the function does, and then you can start to investigate numeric alternatives.

댓글을 달려면 로그인하십시오.

답변 (0개)

카테고리

Help CenterFile Exchange에서 Calculus에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by