Hello. I'm trying to swap the first two numbers of the first and second rows of this test matrix with the last two numbers of the second and third rows. Is there any way to swap these numbers in a matrix that's not one row and/or not on the same row?
x = [1 2 3 4 5;
6 7 8 9 10;
11 12 13 14 15]
The result should be:
x = [9 10 3 4 5;
14 15 8 1 2;
11 12 13 6 7]

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Stephen23
Stephen23 2018년 9월 12일
편집: Stephen23 2018년 9월 12일

1 개 추천

>> x = [1,2,3,4,5;6,7,8,9,10;11,12,13,14,15]
x =
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
>> x([1,4,11,14]) = x([11,14,1,4])
x =
9 10 3 4 5
6 7 8 1 2
11 12 13 14 15
You can easily generate those linear indices with sub2ind.

댓글 수: 1

The code to do it was actually this:
x([1,2,4,5,11,12,14,15]) = x([11,12,14,15,1,2,4,5])
...but thanks! I got the gist of it!

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추가 답변 (1개)

Bruno Luong
Bruno Luong 2018년 9월 12일
편집: Bruno Luong 2018년 9월 12일

1 개 추천

[x(1:2,1:2) x(2:3,4:5)] = deal(x(2:3,4:5),x(1:2,1:2))

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2018년 9월 12일

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2018년 9월 12일

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