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Hi,
I am trying to perform FFT for ambient vibration data and My code calculates such an absurd value like 6.2172e-17 for the first value of Fourier Amplitude Matrix. However, other amplitudes are reasonable and if I plot these amplitudes in loglog figure, I get meaningless plot.
for j=1:3
a{j}=textread(names{j},'%f');
a{j}=detrend(a{j},'constant');
a{j}=detrend(a{j});
if ((60*60)/length(a{j}))==0.02
A{j}=fft(a{j},2^nextpow2(length(a{j})));
A1{j}=abs(A{j}(1:2^nextpow2(length(a{j}))/2))*0.02;
%A1{j}(1)=A1{j}(2);
Fs=50;
f=Fs*(1:2^nextpow2(length(a{j}))/2)/(2^nextpow2(length(a{j})));
figure (j)
loglog(f,A1{j},'b');
title(names1{j});
xlabel('Frequency (Hz)');
ylabel('Fourier Amplitude');
elseif ((60*60)/length(a{j}))==0.01
A{j}=fft(a{j},2^nextpow2(length(a{j})));
A1{j}=abs(A{j}(1:2^nextpow2(length(a{j}))/2))*0.01;
%A1{j}(1)=A1{j}(2);
Fs=100;
f=Fs*(1:2^nextpow2(length(a{j}))/2)/(2^nextpow2(length(a{j})));
figure(j)
loglog(f,A1{j},'b');
title(names1{j});
xlabel('Frequency (Hz)');
ylabel('Fourier Amplitude');
end
end
The cell array are assigned in order to perform 40 FFT calculations for 40 different data texts. What makes Matlab calculate such an absurd value?
답변 (1개)
Dr. Seis
2012년 6월 21일
0 개 추천
Your first amplitude represents 0 frequency. When your data has 0 mean, your first amplitude should also be 0.
카테고리
도움말 센터 및 File Exchange에서 Fourier Analysis and Filtering에 대해 자세히 알아보기
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