Getting data from specific columns in a table

Hello:
I have table_1 and say it has 6 columns. I would to love to have a code that will enable me to get data from a specific column(s) by using the column number or numbers.So lets say I want data from columns 2 and 3, the code should enable me to enter 2 and 3 and then it will search the table and return the data associated with the specified column(s).
Thank you guys.

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Stephan
Stephan 2018년 8월 21일
편집: Stephan 2018년 8월 21일

1 개 추천

You get data from a table by using the dot-notation. Therefore use the name of the column. If your columns are named 1...6 use
table_new = table_old.2
to get data from the column named '2'.
Here is an example:
A = table(['a'; 'b'; 'c'],[1; 2; 3],'VariableNames',{'x', 'y'})
If you use:
A.y
you get an array containing all values of the column named 'y'.
Best regards
Stephan

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This is what I got when I executed it. table_new = table_old.2 | Error: Unexpected MATLAB expression.
Stephan
Stephan 2018년 8월 21일
편집: Stephan 2018년 8월 21일
What is the result if you type:
whos your_table_name
To avoid missunderstanding: table_old is a placeholder since i do not know the name of your table ans the names of their columns.
If i assume that your table is named table_1 and the true name of the columns is 1...6:
result(:,1) = table_1.2;
result(:,2) = table_1.3;
Will give you the columns 2 and 3 from your table in a new array called result.
Nothing at all. My table is named Tabel_A. so i used Table_new = Table_A.2 so i can get the data from column 2 but it doesnt work. I'm new to matlab and I dont know if what i have is even a table ( it shows 100x500 double)
this is what i get:
Name Size Bytes Class Attributes
table_old 1x491 3928 double
Name Size Bytes Class Attributes
Table_A 101x3423 2765784 double
Stephan
Stephan 2018년 8월 21일
편집: Stephan 2018년 8월 21일
You dont use a table. This is an array. If class is not table you do not deal with a table.
Oh sorry for the confusion. It's my fault. I'm new to this so i used the terms wrongly
Stephan
Stephan 2018년 8월 21일
편집: Stephan 2018년 8월 21일
So you use:
B = Table_A(:,2:3)
to get what you want.
Thank you very much. It works

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