Hi, I have an array
S=[ -2.8933 -2.3867 -11.5800 -17.3733 0 22.8400 32.9800 23.0533 6.4933 0.0000 27.2333 44.0333 30.2333 7.1333 0 40.2267 84.8867 138.0800 131.7400 -0.0000]
I need to apply these lines of code on every 5 values
[Max,MaxIdx]=max(S)
[Min,MinIdx]=min(S)
for n=1:5
code(n)=0
if n>=MinIdx & n<=MaxIdx || n<=MinIdx & n>=MaxIdx
if MaxIdx > MinIdx
code(n)=1
else if MinIdx > MaxIdx
code(n)=2
end
end
end
end
the result array code, should be 0 0 0 1 1 0 2 2 2 2 0 2 2 2 2 0 0 2 2 2

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Nicholas Galang
Nicholas Galang 2018년 8월 13일
편집: Nicholas Galang 2018년 8월 13일

0 개 추천

Looping through S and creating a temporary array every 5 values should do the trick.
for i=1:5:length(S)
temp=S(i:i+4);
[Max,MaxIdx]=max(temp);
[Min,MinIdx]=min(temp);
for n=1:5
index=i+n-1;
code(index)=0;
if n>=MinIdx & n<=MaxIdx || n<=MinIdx & n>=MaxIdx
if MaxIdx > MinIdx
code(index)=1;
else if MinIdx > MaxIdx
code(index)=2;
end
end
end
end
code
end

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Lanceric Tse
Lanceric Tse 2018년 8월 13일
I tried them, I reckon it worked but it only returned the values of the last computation
I'm not sure if I understand your complaint. This code snippet will only print out the final code array. If you want all the intermediate code arrays just remove the semicolon in this line,
code(index)=0;
this line
code(index)=1;
and this line.
code(index)=2;
Lanceric Tse
Lanceric Tse 2018년 8월 13일
Got it now, thanks very much

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도움말 센터File Exchange에서 Operators and Elementary Operations에 대해 자세히 알아보기

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