How to save value of find function?

Dear all, How to save the value of x vector in de vector based on find function?

expected results is : de = [1 4 7 3 10 6 90 1.1 80];

x=[ 1 4 7 3 10 6 0 90 1.1 80]; for i=1:10 de = find(x > 0); end

Many thanks...

Answer 1

[Stephen23]

Your loop is superfluous, get rid of it. Simpler with logical indexing:

>> x = [1,4,7,3,10,6,0,90,1.1,80];
>> de = x(x>0)
de =
  1  4  7  3  10  6  90  1.1  80

https://www.mathworks.com/help/matlab/math/matrix-indexing.html

[laith Farhan]

Dear Stephen,

Thanks a lot for your reply.

Is there any way to work with find function because I need to use find?

thanks

[Stephen23]

de = x(find(x>0))

This is simply less efficient than logical indexing.

[laith Farhan]

Dear Stephen, Sorry for disturb you. I am looking for the location of elements. Could you help me please?

for i=1:10 x=[ 1 4 7 -3 10 6 0 -90 1.1 -80]; de = (find(x <= 0)); end expected results is: [ 0 0 0 4 0 0 7 8 0 10];

[Steven Lord]

x=[ 1 4 7 -3 10 6 0 -90 1.1 -80];
de = (find(x <= 0));
z = zeros(size(x));
z(de) = de

[Stephen23]

"expected results is: [ 0 0 0 4 0 0 7 8 0 10];"

With two vectors and a times operation:

>> x = [1,4,7,3,10,6,0,90,1.1,80];
>> (1:numel(x)) .* (x<=0)
ans =
  0  0  0  4  0  0  7  8  0  10

If your professor insists that you use a pointless find, then something like this perhaps:

>> idx = find(x<=0);
>> vec = zeros(size(x));
>> vec(idx) = idx
vec =
  0  0  0  4  0  0  7  8  0  10

[laith Farhan]

Thanks alot that really helpful.