Count conservative occurrences of zeros and if zero appeared for defined number of times it should be changed.
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Hello,
There is an array A size (NxM), each column represents when a signal was created. I need to close that signal if certain time it was not created again and assign -1 value. For example like this:
1 0 1 0 1
0 1 0 1 0
0 0 1 0 0
1 0 0 1 1
0 0 1 1 0
0 1 0 0 0
I need to count consecutive occurrences of zero column-vise, and if zero occurred for defined number of times for example two, it should be changed to -1 and output should look like this:
1 0 1 0 1
0 1 0 1 0
-1 0 1 0 -1
1 -1 0 1 1
0 0 1 1 0
-1 1 0 0 -1
Count conservative occurrences of zeros and if zero appeared for defined number of times it should be changed.
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Jan
2018년 7월 8일
편집: Jan
2018년 7월 8일
If you want to replace the 2nd element after a 1 by -1, if it was a 0 before:
A = double(rand(10, 5) < 0.3); % Some test data
n = 2;
pattern = [1, zeros(1, n)];
for k = 1:size(A, 2)
index = strfind(A(:, k).', pattern);
A(index + n, k) = -1;
end
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Jan
2018년 7월 9일
@Mantas Vaitonis: strfind is not implemented for GPUs. If you have a C compiler installed, I'd suggest to try the MEX function. Which OS do you use? Can you work with UINT8 instead of DOUBLEs?
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