Checking if all strings exist in row of array

So I have an array that has rows of strings(A) and I want to check if another user inputted array of strings(B) is contained in each row of (A). I believe I have it so that it will be true if at least one of the strings in array B is present, but I want them all to have to be present. I put an example below of what I am doing now in a shorter version and it is using numbers instead of strings so I know contains is not for numbers, but I just was trying to be quick. Thanks for your help!

v = [5 4 3 2 1; 4 3 2 6 6; 8 5 0 9 6];
f = input('please input nums to test'); % say it repeats
%and you input an array like [2 6 4]
for i = 1:3
    % I want 2, 6, and 4 for to all have to be be in the row for it 
    % to be true not just one.
    if contains(v(i), f) == 1 
        %Do something
    end
end

Answer 1

[Stephen23]

You could use ismember and all:

mat = [5 4 3 2 1; 4 3 2 6 6; 8 5 0 9 6];
str = input('Please enter numbers to test: ','s');
vec = sscanf(str,'%f',[1,Inf]);
for k = 1:size(mat,1)
    if all(ismember(vec,mat(k,:)))
        ...
    end
end

[Austin Welch]

I am sorry, I am having trouble with this. What I am actually using are strings. I was only using numbers as an example for simplicity.

[Stephen23]

ismember also works with string arrays. Please show the code that you tried.

[Jan]

@Austin Welch: Posting inputs with a different data type does not simplify the problem, but leads to wrong solutions.