How do I make this type of tree in matlab using scatter?

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JoshT_student
JoshT_student 2018년 6월 8일
댓글: JoshT_student 2018년 6월 9일
Hello, I am trying to make the following tree. I have the matrix a with 0's where I should have white boxes and 1's where I should have square black boxes. However, it is extremely difficult to organize all the boxes in the order to make a tree that looks good without big white spaces being where they should not be.
please help. Thanks
Code below
clear;
clc;
%Makes an array of 0's 20X20
a=zeros(20);
%These following elements are to fill each element in array
%%plotmatrix(a);
a(1,4:7)=1;
a(1,11:14)=1;
a(2,2:12)=1;
a(2,14:18)=1;
a(3,1:11)=1;
a(3,13:19)=1;
a(4,1:3)=1;
a(4,5:9)=1;
a(4,12:19)=1;
a(5,2:4)=1;
a(5,7:8)=1;
a(5,11:13)=1;
a(5,15:16)=1;
a(5,19:20)=1;
a(6,2:5)=1;
a(6,8)=1;
a(6,10:13)=1;
a(6,15:16)=1;
a(6,18:20)=1;
a(7,1:4)=1;
a(7,10:14)=1;
a(7,16)=1;
a(7,18:20)=1;
a(8,1:7)=1;
a(8,10:14)=1;
a(8,18:20)=1;
a(9,1:2)=1;
a(9,4:8)=1;
a(9,10:14)=1;
a(9,16:19)=1;
a(10,1:3)=1;
a(10,6:8)=1;
a(10,11:13)=1;
a(10,16:19)=1;
a(11,1:5)=1;
a(11,8)=1;
a(11,11:12)=1;
a(11,15:19)=1;
a(12,2:6)=1;
a(12,11)=1;
a(12,13:19)=1;
a(13,5:8)=1;
a(13,13:18)=1;
a(14,7:9)=1;
a(14,12:14)=1;
a(15,9)=1;
a(15,12)=1;
a(16,9)=1;
a(16,12)=1;
a(17,9)=1;
a(17,12)=1;
a(18,9)=1;
a(18,12)=1;
a(19,12:14)=1;
a(19,7:9)=1;
a(20,1:9)=1;
a(20,12:20)=1;
x=1;
y=1;
scatter(x,y,'fill', 'square', 'k');
hold on;
y1=ones(1,49);
scatter(1.01:0.01:1.49, y1, 'fill', 'square', 'k');
x=1.5;
scatter( x,y, 'fill', 'square', 'k');
  댓글 수: 2
Walter Roberson
Walter Roberson 2018년 6월 8일
I remember this puzzle coming up a couple of years ago, except I think it had a different image. I seem to remember that a good strategy to solve it was given at the time.
The puzzle involved is to be given the marginal counts of the runs and to use the information to reconstruct the image.

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Rik
Rik 2018년 6월 8일
How about imshow (or image)? You have a matrix anyway:
imshow(a)
will show your image (although a bit small). You can use imresize to enlarge the image if you like.

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