how i can find the Entropy for 3 probabilities by matlab?

Hello Every one

Im trying to calculate the entropy for three random values as shown in the following script , but it gives me an error . could any one please help me to find the correct answer. Many thanks.

if true 
p00=[0.1 0.2 0.3 0.4 0.5 0.6 0.7  ];

 p01=[0.1 0.2 0.3 0.4 0.5 0.6 0.7  ];

 p02=[0.1 0.2 0.3 0.4 0.5 0.6 0.7  ];
for i=1:length(p00)

    for j=1:length(p01)

        for k=1:length(p02)

        p03=1-p00(1,i)-p01(1,j)-p02(1,k)

    H(i,j,k) = real((-p00(1,i).*log2(p00(1,i))-(p01(1,j)).*log2(p01(1,j))-p02(i,j,k).*log2((p02(i,j,k)))-p03(i,j,k).*log2((p03(i,j,k)))))

    end

    end
end
  end

Answer 1

[Ankita Bansal]

Hi, first thing which is incorrect in your code is that you are trying to access p02(1,1,2) however p02 is 1x7 matrix. Similarly check for other syntaxes also. Second, I am not getting what are p00, p01 and p02. What is meaning of a vector here?

[Tammun filistin]

p00, p01 and p02 it represent a vectors of probabilities and Im looking for the corresponding entropy for all the compilations of those probabilities. Thanks

[Ankita Bansal]

Hi

   p00=[0.1 0.2 0.3 0.4 0.5 0.6 0.7  ];
   p01=[0.1 0.2 0.3 0.4 0.5 0.6 0.7  ];
   p02=[0.1 0.2 0.3 0.4 0.5 0.6 0.7  ];
  for i=1:length(p00)
      for j=1:length(p01)
          for k=1:length(p02)
             p03=1-p00(1,i)-p01(1,j)-p02(1,k)
             H(i,j,k) = real((-p00(i).*log2(p00(i))-(p01(j)).*log2(p01(j))-p02(k).*log2((p02(k)))-p03*log2(p03)))
          end
      end
  end

is this what you are trying to calculate?