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How to create doubles from cell arrays?

조회 수: 2 (최근 30일)
gsourop
gsourop 2018년 4월 27일
마감: MATLAB Answer Bot 2021년 8월 20일
I would like to ask if there is a more efficient code to do the following task:
a = cell(10,1);
for i = 1 : 10
a{i,1} = randn(200,5);
end
for j =1:5
b{j} = [a{1,1}(:,j) a{2,1}(:,j) a{3,1}(:,j) a{4,1}(:,j) a{5,1}(:,j)];
end
Thank you!

답변 (1개)

Guillaume
Guillaume 2018년 4월 27일
편집: Guillaume 2018년 4월 27일
if there is a more efficient code
Yes, don't use cell arrays!
a = randn(200, 5, 10);
your b{j} is simply
permute(a(:, j, :), [1 3 2])
%or
squeeze(a(:, j, :))
Even simpler, move the j to the third dimension
a = randn(200, 10, 5);
%b{j} would simply be a(:, :, j)
  댓글 수: 2
gsourop
gsourop 2018년 4월 27일
The initial matrices are of this form, I just use randn values in order to replicate the experiment. It is not that I am now starting the calculations. So I have to achieve result 'b' given the form of 'a'.
Guillaume
Guillaume 2018년 4월 27일
Yes, I also used randn purely for demonstration.
Don't use cell arrays if you don't have to. It complicates everything. Since the matrices in your cell array are all the same concatenate them into a 3D matrix and use that from then on.
%a: a cell array of MxN matrices;
bettera = permute(cat(3, a{:}), [1 3 2])
From then on, whenever you wanted to use b{j}, use
bettera(:, :, j)
It is even possible that whatever you wanted to do with each b{j] could be done at once on bettera.

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