sprintf: how to efficiently create a string of 75 numbers, separated by comma
조회 수: 8 (최근 30일)
이전 댓글 표시
I have an array which contains 75 numeric elements. I want to write these numbers as a string separated by a comma. If there were few numbers, I could use 'sprintf' as follows:
A=[1,2];
str=sprintf('%d,%d',A(1:end));
I need an efficient way to do it when there are many entries in A.
댓글 수: 0
채택된 답변
Star Strider
2018년 4월 27일
You can still use sprintf. You just need to create a ‘dynamic’ format string:
A = 1:5;
str = sprintf([repmat('%d,',1, numel(A)-1), '%d'], A)
str =
'1,2,3,4,5'
That will adapt for any ‘A’ vector.
추가 답변 (2개)
Ameer Hamza
2018년 4월 27일
편집: Ameer Hamza
2018년 4월 27일
This will work.
strjoin(string(A), ',')
댓글 수: 2
Walter Roberson
2018년 4월 27일
Note: this requires R2016b or later. Also, it creates a string object output, not a character vector.
Stephen23
2018년 4월 27일
편집: Stephen23
2018년 4월 27일
"I need an efficient way to do it when there are many entries in A."
This is probably about the most efficient way:
A = 1:5;
str = sprintf(',%d',A);
str = str(2:end);
Timing comparisons for 1e4 iterations:
Elapsed time is 0.539053 seconds. % this answer.
Elapsed time is 2.54425 seconds. % Star Strider's answer.
댓글 수: 2
참고 항목
카테고리
Help Center 및 File Exchange에서 Characters and Strings에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!