I have this data :
rank = [18 9 15 17 2 10 13 14 20 5 11 7 8 6 4 19 3 16 1 12 21]
I want to divide data like this
rank a = [18 15 2 13 20 11 8 4 3 1 21] rank b = [9 17 10 14 5 7 6 19 16 12 x]
I want to select x = 18 or is possible select 21 position as x

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Bob Thompson
Bob Thompson 2018년 4월 13일
So you want all even number elements (based on positioning, not value) in one array, and odd number elements in the other?
Muhammad Hafiz
Muhammad Hafiz 2018년 4월 13일
yes Bob, I want all even number in rank a and select rank b into odd number position, I already try this problem but still get some error, please help me to solve this problem

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Bob Thompson
Bob Thompson 2018년 4월 13일

0 개 추천

The sorting is relatively easy with indexing.
rank = [18 9 15 17 2 10 13 14 20 5 11 7 8 6 4 19 3 16 1 12 21]
ranka = rank(1:2:end); % Pull odd numbers (starts at 1)
rankb = rank(2:2:end); % Pull even numbers (starts at 2)
I'm not sure what you mean about the selection of x =

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2018년 4월 13일

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2018년 4월 13일

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