I tried to have a following legend in a plot
legend([Plot1, Plot2, Plot3],'6 bidders (Mean ' + string(mean(OutputSpacing(:,1))) + ', Std: ' + string(std(OutputSpacing(:,1))) +')','12 bidders (Mean ' + string(mean(OutputSpacing(:,2))) + ', Std: ' + string(std(OutputSpacing(:,2))) +')','24 bidders (Mean ' + string(OutputSpacing(:,3)) + ', Std: ' + string(std(OutputSpacing(:,3))) +')')
Then I got a following message
Warning: Ignoring extra legend entries.
> In legend>set_children_and_strings (line 674)
In legend>make_legend (line 346)
In legend (line 294)
In test (line 1001)
Please advise.

 채택된 답변

Star Strider
Star Strider 2018년 4월 5일

0 개 추천

One possible solution:
OutputSpacing = rand(3);
figure
plot(1:3, OutputSpacing, 'p')
lgndcell = regexp(sprintf('%2d Bidders (Mean: %.2f, Std: %.2f)\n', [[6 12 24]; mean(OutputSpacing); std(OutputSpacing)]), '\n', 'split');
legend(lgndcell(1:end-1))
You will probably need to tweak it to work with your data and plots. (It works with this code.)

댓글 수: 2

alpedhuez
alpedhuez 2018년 4월 5일
Thank you.
Star Strider
Star Strider 2018년 4월 5일
As always, my pleasure.

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추가 답변 (1개)

Walter Roberson
Walter Roberson 2018년 4월 5일

0 개 추천

You pass in three handles but six legend strings.

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2018년 4월 5일

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2018년 4월 5일

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