What is the output?

I am trying to check how the loop works hence, I am displaying the value of n in the for loop but it doesn't seem to work. Why doesn't n get displayed and how is the code (loop) working?

h=0.3;
x=0:h:0.8;
for n=4:length((x)-1)
  disp(n)
  % Doing something here
  end

Answer 1

[Walter Roberson]

length of x is 3. When you subtract 1 from a numeric vector you do not change the length so length((x) - 1) is the same length(x) which is 3. So your for loop is

for n=4:3

Which will not execute at all.

Answer 2

[Roger Stafford]

The vector x has only three elements, [0,.3,.6], so the 'for' instruction reads:

for n = 4:2

Therefore the loop will not execute at all, and this accounts for your lack of results.

[Shivangi Srivastava]

If h would have been 0.2 then the for loop would be n = 4:4 right? How does this code get executed and the values of n change?

[Walter Roberson]

No, with 0.2 x would be 0 0.2 0.4 0.6 0.8 which is length 5. When you subtract one from the numeric values the length stays the same, just you would working with -1 -.8 -.6 -.4 -.2. Still length 5. So the loop would be 4:5