wat is function of scale and size?

조회 수: 1 (최근 30일)
Madhava Teja Munagala
Madhava Teja Munagala 2018년 3월 14일
편집: Pawel Jastrzebski 2018년 3월 14일
if size(i,3)>1
i=rgb2gray(i);
wat is size(i,3),here i is image and 3 is what
scale=2; if scale>0 here scale gives what

답변 (1개)

Pawel Jastrzebski
Pawel Jastrzebski 2018년 3월 14일
편집: Pawel Jastrzebski 2018년 3월 14일
size (x,3) calculates the depth of a 3D array.
Function size calculate the dimensions of the array. The additional parameter (1,2,3) tells which size specifically should be calculated.
Consider the examples below and also read on size doc:
% dimensions
x = 5
y = 6
z = 7
% 2D matrix of random values
m2D = rand(x,y)
% 3D matrix of random values
m3D = rand(x,y,z)
% using 'size' on a 2D matrix:
s2D = size(m2D) % gives 'x' and 'y' dimensions
s2Dx = size(m2D,1) % gives 'x' dimension only
s2Dy = size(m2D,2) % gives 'y' dimension only
s2Dz = size(m2D,3) % gives 1, as there's no depth
% using 'size' on a 3D matrix:
s3D = size(m3D) % gives 'x', 'y' and 'z' dimensions
s3Dx = size(m3D,1) % gives 'x' dimension only
s3Dy = size(m3D,2) % gives 'y' dimension only
s3Dz = size(m3D,3) % gives 'z' dimension only
  댓글 수: 2
Madhava Teja Munagala
Madhava Teja Munagala 2018년 3월 14일
Thank u, wat is the output of these code
Pawel Jastrzebski
Pawel Jastrzebski 2018년 3월 14일
편집: Pawel Jastrzebski 2018년 3월 14일
I don't want to be rude, but can't you run the code yourself to find out the output?
The output is explained in the comments.
>> % dimensions
x = 5
y = 6
z = 7
% 2D matrix of random values
m2D = rand(x,y)
% 3D matrix of random values
m3D = rand(x,y,z)
% using 'size' on a 2D matrix:
s2D = size(m2D) % gives 'x' and 'y' dimensions
s2Dx = size(m2D,1) % gives 'x' dimension only
s2Dy = size(m2D,2) % gives 'y' dimension only
s2Dz = size(m2D,3) % gives 1, as there's no depth
% using 'size' on a 3D matrix:
s3D = size(m3D) % gives 'x', 'y' and 'z' dimensions
s3Dx = size(m3D,1) % gives 'x' dimension only
s3Dy = size(m3D,2) % gives 'y' dimension only
s3Dz = size(m3D,3) % gives 'z' dimension only
x =
5
y =
6
z =
7
m2D =
0.1599 0.9759 0.8343 0.9044 0.5714 0.3581
0.6668 0.0309 0.8136 0.6804 0.9817 0.9869
0.0179 0.4939 0.6290 0.3788 0.8497 0.0840
0.1197 0.8627 0.0022 0.6320 0.2834 0.2503
0.9521 0.2429 0.3797 0.2433 0.6825 0.8113
m3D(:,:,1) =
0.0844 0.4379 0.9053 0.7831 0.2488 0.9258
0.5313 0.3504 0.6402 0.6857 0.3193 0.1788
0.8006 0.4785 0.1629 0.4662 0.9108 0.5175
0.7388 0.5874 0.5659 0.2603 0.8852 0.6270
0.1417 0.1458 0.9316 0.5693 0.7946 0.9132
m3D(:,:,2) =
0.6640 0.0850 0.3801 0.3781 0.6853 0.2602
0.3892 0.9224 0.8128 0.2489 0.6203 0.8775
0.7400 0.0536 0.2441 0.2529 0.7467 0.8061
0.8176 0.5270 0.8844 0.7672 0.9773 0.4611
0.6003 0.1189 0.7126 0.0499 0.3839 0.0910
m3D(:,:,3) =
0.5643 0.7267 0.0525 0.9084 0.8506 0.5173
0.1874 0.5158 0.8012 0.5100 0.1445 0.9905
0.5317 0.7906 0.6786 0.6149 0.3705 0.2265
0.3550 0.2045 0.9460 0.3161 0.6224 0.3980
0.3148 0.6781 0.0916 0.0775 0.9976 0.6966
m3D(:,:,4) =
0.0646 0.3191 0.7346 0.4968 0.4658 0.2886
0.7477 0.9861 0.6373 0.0224 0.5609 0.2690
0.4204 0.7182 0.0738 0.0538 0.4945 0.5942
0.8113 0.4132 0.1205 0.1409 0.0678 0.4759
0.3796 0.0986 0.9816 0.8935 0.8976 0.3683
m3D(:,:,5) =
0.6556 0.4391 0.5199 0.5669 0.0478 0.9374
0.9382 0.0273 0.0538 0.6804 0.7383 0.5134
0.6204 0.8762 0.8622 0.3714 0.0380 0.2409
0.2828 0.6101 0.4429 0.0782 0.9542 0.2600
0.2052 0.2036 0.5480 0.4564 0.7424 0.7590
m3D(:,:,6) =
0.9933 0.4306 0.6401 0.3081 0.7598 0.4369
0.3567 0.7307 0.1320 0.4024 0.2909 0.3043
0.7529 0.2612 0.4528 0.8842 0.2774 0.2909
0.1100 0.0948 0.6522 0.7006 0.0061 0.2425
0.5970 0.4510 0.8270 0.2419 0.3747 0.9367
m3D(:,:,7) =
0.8602 0.2698 0.3320 0.5433 0.4825 0.1319
0.3972 0.9897 0.7487 0.2514 0.4427 0.3559
0.4794 0.1837 0.6444 0.5786 0.3118 0.3959
0.5650 0.8617 0.1692 0.9155 0.0553 0.8855
0.4896 0.0326 0.9522 0.8956 0.7538 0.0212
s2D =
5 6
s2Dx =
5
s2Dy =
6
s2Dz =
1
s3D =
5 6 7
s3Dx =
5
s3Dy =
6
s3Dz =
7
>>

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Matrix Indexing에 대해 자세히 알아보기

태그

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by