Hi i have following two cell arrays mul1 and mul2.
I want to multiply each cell of mul1 with corresponding cell of mul2. I am using following code
for i=8
for j=7
mul3{i,j}= mul1{i,j}.*mul2{i,j};
end
end
but it gives error:
Error using .*
Matrix dimensions must agree.
i also tried without using loop but still same issue.
Please help

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@lucksBi: your title and question are both incorrect: it is not possible to multiply cell arrays, and this is not what you are doing. What your code actually does is multiply some (presumably numeric) arrays that happen to be stored in the cells of a cell array. The error you are getting is because they have incompatible sizes, so please tell us what the sizes are when the error occurs:
size(mul1{i,j})
size(mul2{i,j})
lucksBi
lucksBi 2018년 2월 28일
yes you are right. It multiplies values within cells which are numeric values. Size of mul1 is 8x7 cell and mul2 is 8x7 cell.
Result of size is:
for i=1:8
for j=1:7
a= size(mul1{i,j})
b= size(mul2{i,j})
mul3{i,j}= mul1{i,j}.*mul2{i,j};
end
end
Result:
a = 1 0
b = 0 0
Stephen23
Stephen23 2018년 2월 28일
lucksBi: I did not ask you for the size of mul1 or mul2. Please read my comment again.

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Birdman
Birdman 2018년 2월 28일

0 개 추천

Try this:
res=cellfun(@times,mul1,mul2,'uni',0)

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lucksBi
lucksBi 2018년 2월 28일
ThankYou for your reply.. It gives same error as above
Andrei Bobrov
Andrei Bobrov 2018년 2월 28일
편집: Andrei Bobrov 2018년 2월 28일
@lucksBi: All right!
>> mul1
mul1 =
8×7 cell array
[1×0 double] [ -0.1140] [ -0.2700] [1×2 double] [1×2 double] [] []
[1×0 double] [1×0 double] [1×3 double] [ 0.1967] [1×0 double] [1×2 double] [1×4 double]
[ -0.1140] [1×0 double] [1×0 double] [1×3 double] [1×2 double] [1×0 double] [1×3 double]
[ -0.2700] [1×3 double] [1×0 double] [1×0 double] [ 0.2598] [ -0.8066] [1×3 double]
[1×2 double] [ 0.1967] [1×3 double] [1×0 double] [1×2 double] [ -0.0151] [1×4 double]
[1×2 double] [1×0 double] [1×2 double] [ 0.2598] [1×2 double] [1×0 double] [1×2 double]
[1×0 double] [1×2 double] [1×0 double] [ -0.8066] [ -0.0151] [1×0 double] [1×2 double]
[ -0.0974] [1×4 double] [1×3 double] [1×3 double] [1×4 double] [1×2 double] [1×2 double]
>> mul2
mul2 =
8×7 cell array
[] [ 1] [ 1] [1×2 double] [1×2 double] [] []
[] [] [1×3 double] [ 1] [] [1×2 double] [1×4 double]
[ 1] [] [] [1×3 double] [1×2 double] [] [1×3 double]
[ 1] [1×3 double] [] [] [ 1] [ 1] [1×3 double]
[1×2 double] [ 1] [1×3 double] [] [1×2 double] [ 1] [1×4 double]
[1×2 double] [] [1×2 double] [ 1] [1×2 double] [] [1×2 double]
[] [1×2 double] [] [ 1] [ 1] [] [1×2 double]
[ 1] [1×4 double] [1×3 double] [1×3 double] [1×4 double] [1×2 double] [1×2 double]
>> cellfun(@times,mul1,mul2,'un',0)
ans =
8×7 cell array
[] [ -0.1140] [ -0.2700] [1×2 double] [1×2 double] [] []
[] [] [1×3 double] [ 0.1967] [] [1×2 double] [1×4 double]
[ -0.1140] [] [] [1×3 double] [1×2 double] [] [1×3 double]
[ -0.2700] [1×3 double] [] [] [ 0.2598] [ -0.8066] [1×3 double]
[1×2 double] [ 0.1967] [1×3 double] [] [1×2 double] [ -0.0151] [1×4 double]
[1×2 double] [] [1×2 double] [ 0.2598] [1×2 double] [] [1×2 double]
[] [1×2 double] [] [ -0.8066] [ -0.0151] [] [1×2 double]
[ -0.0974] [1×4 double] [1×3 double] [1×3 double] [1×4 double] [1×2 double] [1×2 double]
>>
Birdman
Birdman 2018년 2월 28일
It should not. It worked for me.

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