sum

i have an array whose size is 467*320 = 149440 i mean,

Y = [y1 y2 ... y149440] and i'd like to do that :

Y_1 =[y1+y2+y3...+y320 y321+y322+y321+...y640 .....]

y11=y1+y2+...+y320

y12=y321+y322...+y640

:

:

that is to say; the first element of Y_1 is sum of the first 320 elements and the second element of that is sum of the second 320 elements and going on like this and the size of Y_1 will be 1x467(1x149440/320)...

And i will have Y_2 like Y_1

for Y_2 : Y_2=[y1+y2+y3+...+y320 ..... .... ](1x467)

y21=y1+y2+y3+...+y320

:

:

at the end i create X-array that is

X = [y11+y21 y12+y22 y13+y23 ......]

this is my question :)

i thank you for your helps...

Answer 1

[Matt Fig]

I am a little confused, do you mean like this:

Y = reshape(1:18,6,3)  % A manageable dimension.
Y_1 = sum(Y,2)

So in your case it would be

Y_1 = sum(Y,2).';

.

.

Or do you mean, more like this:

Y = 1:18
Y_1 = sum(reshape(Y,3,6))

So in your case it would be

Y_1 = sum(reshape(Y,320,467))

[osman yurdakul]

let me explain step-by-step:

first of all i have an array called Y whose dimension is 1x149440

Y =[y1 y2 y3 .......... y149440];

and i want to make Y_1 array whose dimension is 1x467

Y_1 = [y1+y2+y3+...+y320 y321+y322+y323+...+y640];

i mean the first element of Y_1-array is sum of the first 320(1:320) elements of Y-array and the second element of Y_1-array is sum of the second 320(321:640) of Y-array

[osman yurdakul]

Y_1 = [y1+y2+y3+...+y320 y321+y322+y323+...+y640 ...........];

i mean the first element of Y_1-array is sum of the first 320(1:320) elements of Y-array and the second element of Y_1-array is sum of the second 320(321:640) of Y-array and going on like this..dimension of Y_1 is 1x467...

[Matt Fig]

So then my second example is the solution to your problem, correct?

Y = rand(1,149440);

Y_1 = sum(reshape(Y,320,467));

size(Y_1)

ans =

1 467

[osman yurdakul]

yes it is...

i tried and saw it was running :D thank you for your helping...