if inside of for loop
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I don't know what is wrong with this code. The code works when I don't include the if statement. Any idea?
for i = 1:3
if rt > 100 & rt < 1000
average(i) = mean(rt(cue==i))
dev(i) = std(rt(cue==i))
end
end
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the cyclist
2018년 2월 19일
You are leaving too much for us to guess at, which makes it difficult for us to help you.
Please describe what you mean by "doesn't work" in more detail. Does the code give an error? If so, tell us the complete error message, and which line it occurs on.
If it does not give an error, but just an unexpected result, tell us the expected and actual result.
In general, it would be better to supply code that we can actually run ourselves (e.g. by supplying the values of rt and cue.)
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Jan
2018년 2월 19일
편집: Jan
2018년 2월 20일
Or perhaps:
match = (rt > 100 & rt < 1000);
rtx = rt(match);
cuex = cue(match);
for i = 1:3
average(i) = mean(rtx(cuex==i))
dev(i) = std(rtx(cuex==i))
end
Note that "if rt > 100 & rt < 1000" is evaluated as:
if all(rt > 100 & rt < 1000) && ~isempty(rt)
댓글 수: 2
Jan
2018년 2월 20일
@Alejandro: Yes, this way a typo. Inside the loop rtx and cuex are needed. I've fixed this in my answer.
추가 답변 (1개)
Birdman
2018년 2월 19일
편집: Birdman
2018년 2월 19일
You probably forgot subscripting of rt.
for i = 1:3
if rt(i) > 100 & rt(i) < 1000
average(i) = mean(rt(cue==i))
dev(i) = std(rt(cue==i))
end
end
댓글 수: 2
Birdman
2018년 2월 20일
But again
rt(cue==i)
this will result in an array. You may perhaps do it before the loop and give it subscripted to for loop as
rt=rt(cue==i);
for i=1:3
if rt(i)...
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