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can you please explain the working of following syntax?

조회 수: 1 (최근 30일)
Siddhesh Karbhari
Siddhesh Karbhari 2018년 1월 14일
마감: MATLAB Answer Bot 2021년 8월 20일
z=D{extrema(4*(i-1)+1)}(rx,ry,rz);
it is continuously giving 'Bad cell reference operation.' error.
extrema=zeros(1,4*number);
idx= extrema==0;
extrema(idx)=[];
extr_volume=length(extrema)/4;
for i=1:extr_volume
x=floor((extrema(4*(i-1)+3)-1)/(n/(2^(extrema(4*(i-1)+1)-2))))+1;
y=mod((extrema(4*(i-1)+3)-1),m/(2^(extrema(4*(i-1)+1)-2)))+1;
rx=x+1;
ry=y+1;
rz=extrema(4*(i-1)+2);
z=D{extrema(4*(i-1)+1)}(rx,ry,rz);
size(z)
if(abs(z)<threshold)
extrema(4*(i-1)+4)=0;
end
end

답변 (1개)

Star Strider
Star Strider 2018년 1월 14일
The code you posted does not make sense. It sets ‘extrema’ to an empty array, so all references to elements of ‘extrema’ would throw errors, because they do not exist.
  댓글 수: 3
Star Strider
Star Strider 2018년 1월 14일
I cannot run the code that you attached.
I will delete my Answer in a few hours.
Walter Roberson
Walter Roberson 2018년 1월 14일
We do not have your b.jpg to test with. I copied the demo image car2.jpg to b.jpg and ran the code without difficulty.
"Bad cell reference operation" is not a MATLAB error message. Is it possible that you were running under Octave?

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