Matrix manipulation using reshape

If A=
1 0 0 0 0 0 0 0 0 0
0 2 0 0 0 0 0 0 0 0
0 0 3 0 0 0 0 0 0 0
0 0 0 4 0 0 0 0 0 0
0 0 0 0 5 0 0 0 0 0
0 0 0 0 0 6 0 0 0 0
0 0 0 0 0 0 7 0 0 0
0 0 0 0 0 0 0 8 0 0
0 0 0 0 0 0 0 0 9 0
0 0 0 0 0 0 0 0 0 10
I got B =
1 2 0 0 0 0 0 0 0 0
1 2 0 0 0 0 0 0 0 0
0 0 3 4 0 0 0 0 0 0
0 0 3 4 0 0 0 0 0 0
0 0 0 0 5 6 0 0 0 0
0 0 0 0 5 6 0 0 0 0
0 0 0 0 0 0 7 8 0 0
0 0 0 0 0 0 7 8 0 0
0 0 0 0 0 0 0 0 9 10
0 0 0 0 0 0 0 0 9 10
using
B = reshape(repmat(max(reshape(A,2,[])),2,1),size(A)).
But if i want to get C =
1 0 3 0 0 0 0 0 0 0
0 2 0 4 0 0 0 0 0 0
1 0 3 0 0 0 0 0 0 0
0 2 0 4 0 0 0 0 0 0
0 0 0 0 5 0 0 8 0 0
0 0 0 0 0 6 0 0 9 0
0 0 0 0 0 0 7 0 0 10
0 0 0 0 5 0 0 8 0 0
0 0 0 0 0 6 0 0 9 0
0 0 0 0 0 0 7 0 0 10
from A how the reshape can be written?

댓글 수: 2

Roger Stafford
Roger Stafford 2017년 12월 18일
How would you generalize what is desired for an arbitrary size diagonal matrix? It is fairly easy to produce the desired result for your particular size.
Prabha Kumaresan
Prabha Kumaresan 2017년 12월 18일
I need to have random grouping of rows which reults in sharing their values.

답변 (1개)

Roger Stafford
Roger Stafford 2017년 12월 18일

0 개 추천

If the "grouping" is to be randomly determined, do this:
n = size(A,1);
p = mod((0:n-1)+randi(n-1,1,n),n)+1; % p(k) never equals k
B = A;
for k = 1:n
B(p(k),k) = B(k,k);
end
If you have already determined a vector p to be used, then leave out the second line.

댓글 수: 1

The following code executes but I am unable to get the random grouping of users.
N_UE=[10 20 30 40 50];
N_SC=[60 70 80 90 100];
for t= 1:length(N_UE)
for r = 1:length(N_SC)
C=rand(N_UE(t),N_SC(r));
s = size(C,1);
p = mod((0:s-1)+randi(s-1,1,s),s)+1; % p(k) never equals k
B = C;
for k = 1:s
B(p(k),k) = B(k,k);
end
end
end

이 질문은 마감되었습니다.

질문:

2017년 12월 18일

마감:

2021년 8월 20일

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