how to sort in increasing order using loop?

for i=1:6
A(i)=input('')
end
for i=1:6
for j=1:5
if A(j)>=A(j+1)
B=A(j);
A(j)=A(j+1);
A(j+1)=B;
end
end
end

댓글 수: 6

Hello baiti, what don't you like about this? It's a bubble sort in increasing order and it works.
baiti
baiti 2017년 12월 16일
then, i think my matlab is the problem. i really dont have any idea why it wont work on my matlab. any suggestion?
It's cleaner to put A = zeros(1,6) at the beginning, so that if you run the script more than once you get a fresh start for A. I put disp(A) at the end as well, so that you can see the results of your efforts.
Image Analyst
Image Analyst 2017년 12월 16일
To format your code read this
Why don't you just use the built-in sort() function?
Jan
Jan 2017년 12월 17일
@baiti: It seems like you have a problem running this code. Then it would be useful, if you mention what the problem is. "it wont work on my matlab" does not allow to reconsider, why you are not satisfied.
Manish Kumar
Manish Kumar 2020년 6월 26일
Do you want better algorithm than this?

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답변 (1개)

rohan hazarika
rohan hazarika 2020년 9월 18일

0 개 추천

for i=1:6
A(i)=input('')
end
for i=1:6
for j=1:5
if A(j)>=A(j+1)
B=A(j);
A(j)=A(j+1);
A(j+1)=B;
end
end
end

카테고리

도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

질문:

2017년 12월 16일

답변:

2020년 9월 18일

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