Making a three column matrix

Hi everyone! I am having trouble with the following: I have built a 31 row by 3 columns ceros matrix and I am trying to index values to each column, I want my first column to go from 140 to 440(this are lengths), but when trying to do so my values start from 0, then 140, then 440... Then in the second column I want the values of column 1 to appear because I need to compare how many lengths are being acumulated( this to later build a histogram..) I would very much appreciate your help!

[Raul Andres Lopez Romero]

Can you provide an example, of what you want? i think you want column 1 140 141 142 . . . 440 but i'm not sure ...

[Jan]

Please post your code. How could a reader suggest an improvement without seeing the code?

[Liliana Sierra]

yes I want column one to go from 140,141,142,143 I am trying this:

c=zeros(300,3); c(:,1)=[140:1:440]'; c(140,1)=140

[Liliana Sierra]

it was a 300 row by 1 column matrix.. sorry I got confused when I first posted the question..

Answer 1

[Raul Andres Lopez Romero]

Your code has only one error when you set the C matrix in 300 rows and 3 columns, and try to fill it with numbers starts in 140 to 440 with steps of 1 unit you have a 301 elements so, the C matrix needs to be 301 rows not 300. (if the number starts in 141 so, there is a 300 elements vector)

the code:

C=zeros(301,3);
C(:,1)=[140:1:440]'

Answer 2

[Liliana Sierra]

Thank you!