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Overlapping time-intervals

조회 수: 89(최근 30일)
I have two date-time arrays a and b.
a for start time and b for end time (above horizontal line on the picture).
What is the way to parse them and get what is beneath horizontal line on the picture?

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Star Strider
Star Strider 12 Nov 2017
If each has a unique set of data by date (not duplicated in the other records), combining and sorting by date would work.
If there are duplicates, then you have to decide how to combine the duplicated values.

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채택된 답변

David Goodmanson
David Goodmanson 14 Nov 2017
편집: David Goodmanson 14 Nov 2017
Hi Rostislav
It looks like you want the union of closed intervals. Here is some code that I think does the job. When the ends of intervals have the same value, it works because the sort function is stable and preserves ordering for ties.
% Nx2 matrix of endpoints x1, x2 of intervals
x = [8 10; 2 4; 4 5; 5 7; 9 11; 15 16; 14 17; 10 12]
% -----plot it first
nline = repmat((1:size(x,1))',1,2);
plot(x',nline','o-')
ylim([-.5*nrow 1.5*nrow])
% ----- find union of intervals
x = sort(x,2);
nrow = size(x,1);
[x ind] = sort(x(:));
n = [(1:nrow) (1:nrow)]';
n = n(ind);
c = [ones(1,nrow) -ones(1,nrow)]';
c = c(ind);
csc = cumsum(c); % =0 at upper end of new interval(s)
irit = find(csc==0);
ilef = [1; irit+1];
ilef(end) = []; % no new interval starting at the very end
% y matrix is start and end points of the new intervals, y1,y2
%
% ny matrix is the corresponding indices of the start and end points
% in terms of what row of x they occurred in.
y = [x(ilef) x(irit)]
ny = [n(ilef) n(irit)]

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Rostislav Teryaev
Rostislav Teryaev 14 Nov 2017
Thank you for your reply. Works like a charm! I did my one with loops, but your many times faster.
function [ a,b ] = intervalsSort( a, b )
tf = 1;
f = 1;
[a, ind] = sort(a);
b = b(ind);
for i = 1:length(a)
if i == 1
c(1) = a(1);
d(1) = b(1);
else
f = 1;
for j = 1:length(c)
if c(j)<=a(i) & a(i)<=d(j)
if d(j) < b(i)
d(j) = b(i);
end
f = 0;
end
end
if f
c = [c a(i)];
d = [d b(i)];
end
end
end
a = c;
b = d;
end
Ted Shultz
Ted Shultz 21 Aug 2020
This is really great code. I fixed a small type, and added comments so others can learn from it as well.
intervalsIn = [8 10; 2 4; 4 5; 5 7; 9 11; 15 16; 14 17; 10 12]
% -----plot it first
nline = repmat((1:size(intervalsIn,1))',1,2);
nrow = size(intervalsIn,1);
plot(intervalsIn',nline','o-')
ylim([-.5*nrow 1.5*nrow])
% ----- find union of intervals
intervalsIn = sort(intervalsIn,2); % make the pairs always increasing pairs
[intervalsIn, ind] = sort(intervalsIn(:)); % sorts all the input values, and keepts track of how they moved around
c = [ones(1,nrow) -ones(1,nrow)]'; % this is a matrix that keeps track of when intervals start (1) and stop (-1)
c = c(ind); % put in order of occurrence
csc = cumsum(c); %sum up starts (1) and stops (-1) , will be =0 at upper end of new interval(s)
irit = find(csc==0); % find index locations of 0 (ends of intervals)
ilef = [1; irit+1]; % start of intervals index is at the very start (1) and one after all the other ends
ilef(end) = []; % no new interval starting at the very end
% spansOut matrix is start and end points of the new intervals, y1,y2
spansOut = [intervalsIn(ilef) intervalsIn(irit)]

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추가 답변(1개)

Hung Doan
Hung Doan 19 Jul 2019
nrow is undefined in the initial plotting but other than that, works like a charm!

  댓글 수: 2

Rostislav Teryaev
Rostislav Teryaev 23 Jul 2019
I want to mention that poposed solution is very nice, but I remember that it has some kind of a bug. I can not point in which case, but I faced it in my project which I was doing that times. My solutions is slower but did not gave an error.
You can use any solution you want, but consider what I said.
Ted Shultz
Ted Shultz 21 Aug 2020
Small typo in original answer, code could be be:
intervalsIn = [8 10; 2 4; 4 5; 5 7; 9 11; 15 16; 14 17; 10 12]
% -----plot it first
nline = repmat((1:size(intervalsIn,1))',1,2);
nrow = size(intervalsIn,1);
plot(intervalsIn',nline','o-')
ylim([-.5*nrow 1.5*nrow])
% ----- find union of intervals
intervalsIn = sort(intervalsIn,2); % make the pairs always increasing pairs
[intervalsIn, ind] = sort(intervalsIn(:)); % sorts all the input values, and keepts track of how they moved around
c = [ones(1,nrow) -ones(1,nrow)]'; % this is a matrix that keeps track of when intervals start (1) and stop (-1)
c = c(ind); % put in order of occurrence
csc = cumsum(c); %sum up starts (1) and stops (-1) , will be =0 at upper end of new interval(s)
irit = find(csc==0); % find index locations of 0 (ends of intervals)
ilef = [1; irit+1]; % start of intervals index is at the very start (1) and one after all the other ends
ilef(end) = []; % no new interval starting at the very end
% spansOut matrix is start and end points of the new intervals, y1,y2
spansOut = [intervalsIn(ilef) intervalsIn(irit)]

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