Extreact Information from a String
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Hello, I do have the following Code
d = dir('/home/user/Documents/Data*.inp');
names = {d.name}
which gives me an Array of Strings.
names(1) is like = "Data_c11_t3.322111_id01111_Units.inp"
names(2) is like = "Data_c101_t4.32111_id01112_Units.inp"
etc.
Now I want to extract the time, which is in the name after "t". How can I extract the time in such a format?
Any suggestions?
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채택된 답변
KL
2017년 11월 2일
편집: KL
2017년 11월 2일
regexp would be the best idea, I've no big experiences with it, I'll give it a shot anyway,
names = {'Data_c11_t3.322111_id01111_Units.inp';'Data_c101_t4.32111_id01112_Units.inp'};
t = regexp(names,'[0-9]+\.+[0-9*]+','match')
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Guillaume
2017년 11월 3일
To each their own opinion of course. Regular expressions are designed to extract specific patterns in strings, which, in my opinion is exactly the problem at hand.
추가 답변 (2개)
Jos (10584)
2017년 11월 3일
Use a sscanf to read the number between the _t and _id, ignoring the varying number after the _c. Use cellfun to apply this to all cells:
names = {'Data_c11_t3.322111_id01111_Units.inp' ; 'Data_c101_t4.32111_id01112_Units.inp'} ;
T = cellfun(@(N) sscanf(N,'Data_c%*d_t%f_id'), names) % "%*d" = the * means skip
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Coco Newton
2019년 8월 2일
@Jos, this is a great answer
How would I adapt the sscanf formatSpec to extract 130 as a numeric value from this string? I have attached the string array variable that this is example string is taken from.
'Position: (19.59862|1.8|53.84677)Rotation: (0 | 130 | 0)'
Many thanks!
Jos (10584)
2019년 8월 5일
Thanks :-) Something along these lines should work for your input
str = 'Position: (19.59862|1.8|53.84677)Rotation: (0 | 130 | 0)'
A = sscanf(str, 'Position: (%*f|%*f|%*f)Rotation: (%*d | %d | %*d)')
KSSV
2017년 11월 2일
편집: KSSV
2017년 11월 2일
str = 'Data_c11_t3.322111_id01111_Units.inp' ;
idx = strfind(str,'_') ;
str2num(str(idx(2)+2:idx(3)-1))
Using regexp:
str = 'Data_c11_t3.322111_id01111_Units.inp' ;
N = str2num( regexprep( str, {'\D*([\d\.]+\d)[^\d]*', '[^\d\.]*'}, {'$1 ', ' '} ) ) ;
t = N(2)
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