t1 = 588; %k
do = 3.5; % in
di = 3.0; % in
kp = 21.6; %W/(m*K)
ta = 294; % K
ts = 255.4; %k
h = 48.3; %W/(m^2*K)
deltar = 1; % in of calcium silicate insulation
e = .76;
at = pi*(do+2*deltar);
alm1 = (pi*(do-di))/(log(do/di));
alm2 = (2*pi*deltar)/log(do+2*deltar/do);
o = .0000000567; %W/(M^2*k^4)
d = .5; %do-di(in)
syms t2 t3 ki
eq1 = ki==.044+.0001144*(.5*(t2+t3)-283.333)
eq2 = 1/((d/(2*kp*alm1))+(deltar/ki*alm2))==(h*at(t3-ta)+e*o*at(t3^4-ts^4))/(t1-t3)
eq3 = (2*kp*alm1*(t1-t2))/((d)==h*at(t3-ta)+e*o*at(t3^4-ts^4))
[t2,t3,ki] = vpasolve([eq1,eq2,eq3],[t2,t3,ki],[0 inf;0 1])
t2 = double(t2)
t3 = double(t3)
ki = double(ki)
the error is in the eq2 line, eq1 seems to work fine.

댓글 수: 4

Star Strider
Star Strider 2017년 10월 19일
In your code, ‘at’ is a single scalar value. It is not a function or an array, yet you are addressing it as one or the other (probably as a function) in ‘eq2’ and ‘eq3’.
You need to decide what you want to do with it.
Nate Mahorner
Nate Mahorner 2017년 10월 19일
Ended up fixing this problem! Was going to delete but figured if I could help someone else in the future then I'll leave it up. The problems in eq2 and eq3 were I needed *s in front of all the parentheses which I somehow forgot. Hope this helps someone!
Nate Mahorner
Nate Mahorner 2017년 10월 19일
@star strider I figured it out right before you answered! Thank you so much for the quick help!
Star Strider
Star Strider 2017년 10월 19일
The mystery nevertheless continues, since ‘s’ — either as a function or an array — appears nowhere in your code (that I can see).
Resolved it seems, regardless.

댓글을 달려면 로그인하십시오.

 채택된 답변

Birdman
Birdman 2017년 10월 19일

0 개 추천

You forgot to put an operator in front of your at variables in eq2 and eq3. Also, in the vpasolve function, choose your initial guess wisely. If you don't indicate an initial guess for your equations, MATLAB still finds answers. Hope this helps.

댓글 수: 1

Nate Mahorner
Nate Mahorner 2017년 10월 19일
I figured it out right before you answered! Thank you so much for the quick help!

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Walter Roberson
Walter Roberson 2017년 10월 19일

0 개 추천

You have at(t3-ta) and at(t3^4-ts^4) in that line, but at is not a function and and t3-ta and t3^4-ts^4 are not valid indices into the at variable

카테고리

도움말 센터File Exchange에서 Mathematics에 대해 자세히 알아보기

질문:

2017년 10월 19일

댓글:

2017년 10월 19일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by