I'm trying to plot elements from an array of solutions (value of percentage), against a changing parameter ABP. However I only get an empty figure.
valueofPercentage= [1 ... n] ABP=[1 ... n] , where n corresponds to 200 elements.
This is the code:
for s=1:1:200
ABP(P_a_b)=s;
end
for n=length(valueofCBF)
percentage= ((valueofCBF(:,1) - CBF_base)/ CBF_base)*100
valueofPercentage(n)=percentage;
end
for a=length(ABP)
figure(1)
hold on;
plot(ABP(a,:),valueofPercentage(a,:))
end
hold off;

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Birdman
Birdman 2017년 10월 19일
What is P_a_b? You did not define valueofCBF. You did not define CBF_base. This code is wrong. Correct them.
gorilla3
gorilla3 2017년 10월 19일
P_a_b is a parameter that I use previously in the code, and I declared CBF_base as =9.003. But this is unnecessary information for this question. I need help with the syntax of the plot.
Rik
Rik 2017년 10월 19일
편집: Rik 2017년 10월 19일
You wrote for n=length(valueofCBF), usually that's an error and people mean for n= 1: length(valueofCBF). Same goes for the other for-loop.
There is a more fundamental problem: you are plotting a single value (ABP(a)) against a vector (valueofPercentage). This will result in an error.
Also, you should pre-allocate the vector valueofPercentage.
gorilla3
gorilla3 2017년 10월 19일
Thanks, I changed it to n=1:length(valueCBF) and similarly for the next for loop.
Basically, in the workspace of the variables I obtain a 1x200 output for each: valuesofCBF and ABP. So I would like to plot element 1xn of ABP against 1xn of valueCBF
Rik
Rik 2017년 10월 19일
Why don't you use plot(ABP,valueCBF) then? If you want to plot individual points one by one, make sure to include a hold on after the first plot and using a format for plot that shows points, like plot(ABP(a),valueCBF(a),'*')
gorilla3
gorilla3 2017년 10월 19일
Thanks Rik!

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