I am writing a code that will check two numbers whether they are relatively prime or not if they are it would return 1 else 00the problem is that i am getting 1 all the times. Kindly help me midfy my code.
조회 수: 6 (최근 30일)
이전 댓글 표시
function [r]=prime(a,b)
a=input('Enter 1st number=');
b=input('Enter 2nd number=');
% factors for 1st number
K=1:a;
D1 = K(rem(a,K)==0)
% factors for 2nd number
K=1:b;
D2 = K(rem(b,K)==0)
n1=length(D1);
n2=length(D2);
for i=2:n1
for o=2:n2
if (D1(i)==D2(o))
r=0;
break
else
if (D1(i)~=D2(o))
r=1;
end
end
end
end
댓글 수: 2
MUTHUKUMAR SETHURAM
2017년 10월 11일
편집: Walter Roberson
2017년 10월 11일
NumbersRange = 47 : 97;
Prime_Index = isprime(NumbersRange);
NumbersRange(Prime_Index)
채택된 답변
Walter Roberson
2017년 10월 11일
You have a break within a double-nested for loop. That break is only going to break from the inner for loop: you keep running the outer for loop. As long as at least one place a 1 is assigned, then the only thing that has any effect on the output is the last iteration of the outer for loop, because you keep running the outer loop after the inner break.
Your code has another bug, by the way: 1 will divide all values, and when you compare the ones from both sides you say "No, not relatively prime"
Your code is quite inefficient. You should consider using intersect() or ismember()
댓글 수: 3
Walter Roberson
2017년 10월 11일
Minimal modification (rather than "good code")
r = 1;
for i=2:n1
for o=2:n2
if (D1(i)==D2(o))
r=0;
break
else
if (D1(i)~=D2(o))
r=1;
end
end
if r == 0
break
end
end
추가 답변 (1개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!