Working with a three dimensional matrix

조회 수: 1 (최근 30일)
Pepa
Pepa 2011년 1월 24일
I have a matrix with three dimensions, and I need to take two dimensions through the use of cycle FOR.
For example:
Name variable Value
k <39x17x60>
And I need this:
a = 60;
for i = 1:60;
l = k...; %size of l <39x17>
xlswrite...;
end

채택된 답변

Oleg Komarov
Oleg Komarov 2011년 1월 25일
The problem is how you construct kunn, in general there are so many nested loops that my suspect is you end up overwriting the data, go in debug mode and see what happens each time you increase the frist loop and so on:
function[F0mean,F0max,F0min,F0max_min,F0std,F0median,relF0VR,relF0SD,...
Emean,Emax,Emin,Emax_min,Estd,Emedian,TEO,Jmean,...
Jmax,Jmin,Jmax_min,Jstd,Jmedian,Smean,Smax,Smin,...
Smax_min,Sstd,Smedian,F1mean,F1max,F1min,F1max_min,F1std,...
F1median,F2mean,F2max,F2min,F2max_min,F2std,F2median]...
= HRA()
[wav,lab]=databaze;
wav = wav';
lab = lab';
L = length(wav);
for j = 2:L+1
brd = process_lab_file(lab{j-1});
label = brd(:,1);
K = length(label);
for i = 1:K
[F0mean,F0max,F0min,F0max_min,F0std,F0median,relF0VR,relF0SD,...
Emean,Emax, Emin,Emax_min, Estd, Emedian, TEO,...
Jmean,Jmax,Jmin,Jmax_min,Jstd,Jmedian,...
Smean,Smax,Smin,Smax_min,Sstd,Smedian,...
F1mean,F1max,F1min,F1max_min,F1std,F1median,...
F2mean,F2max,F2min,F2max_min,F2std,F2median]=extr_part_of_sig(wav{j-1},label(i),lab{j-1});
priznaky =...
[F0mean,F0max,F0min,F0max_min,F0std,F0median,relF0VR,relF0SD,...
Emean,Emax, Emin,Emax_min, Estd, Emedian, TEO,...
Jmean,Jmax,Jmin,Jmax_min,Jstd,Jmedian,...
Smean,Smax,Smin,Smax_min,Sstd,Smedian,...
F1mean,F1max,F1min,F1max_min,F1std,F1median,...
F2mean,F2max,F2min,F2max_min,F2std,F2median];
O = length(priznaky);
for o = 1:O
zap(o,i) = priznaky(o);
end
end
F = length(priznaky);
for i = 1:K
for a = 1:F
kunn(a,j-1,i) = zap(a);
end
end
end
S = length(label);
jaj = zeros(39,17);
for f = 1:S
jaj = kunn(:,:,2);
koj = jaj';
%xlswrite('ZK.xls', koj, label{i}, 'B2');
end
  댓글 수: 1
Pepa
Pepa 2011년 1월 25일
In debug I found error. You have right. Matrix in kunn is same...

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Kenneth Eaton
Kenneth Eaton 2011년 1월 24일
If you're asking how you would index k in your loop to get a 2-D submatrix, you would do the following:
l = k(:,:,i);
  댓글 수: 14
Oleg Komarov
Oleg Komarov 2011년 1월 25일
isequal(kunn(:,:,1),kunn(:,:,2)) should be 0, can you confirm?
Pepa
Pepa 2011년 1월 25일
No i can't. isequal(kunn(:,:,1),kunn(:,:,2)) result is logical 1. And this is my problem.

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Creating and Concatenating Matrices에 대해 자세히 알아보기

태그

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by