Nested function not assigning value to global variable
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My main script invites a subfunction, which then invites different subfunctions. I want these subfunctions to modify global variables. A simpified example:
a=9;
b=2;
global p
myfunc(a,b);
display Result:
p
function [varargout] = myfunc(a,b);
arr=[a;b];
varargout={arr};
end
mysecondfunction(arr);
prod = arr(1)*arr(2);
p = prod;
end
When the main script calls p again it is empty. Why is this so and how can I fix it?
댓글 수: 3
John D'Errico
2017년 9월 1일
UGH!!!!!!! Ugly, nasty code.
You solve the problem most easily by not using globals at all.
It is a bad idea to use globals in the first place. This is yet another reason why. You don't need globals. Most new users think they do, and eventually learn why not. But they make for nasty, bad code that will be difficult to debug.
As bad an idea is to use variables named prod, or other names that are already used for function names. When you name them that, the function prod will no longer work properly.
채택된 답변
KSSV
2017년 9월 1일
You have to assign p...you have not yet assigned it.
a=9;
b=2;
global p
p = rand ;
myfunc(a,b);
display Result:
p
function [varargout] = myfunc(a,b);
arr=[a;b];
varargout={arr};
end
mysecondfunction(arr);
prod = arr(1)*arr(2);
p = prod;
end
추가 답변(1개)
Stephen23
2017년 9월 1일
편집: Stephen23
2017년 9월 1일
Get rid of the global.
Globals do not solve anything, no matter how much beginners love using them.
It is not clear what your (buggy, non-working, incomplete) code is supposed to do, but making a nested function work correctly is very simple _when you avoid using evil global:
function p = test2
p = [];
myfunc(9,2);
function myfunc(varargin);
p = prod([varargin{:}]);
end
end
and tested:
>> test2()
ans = 18
And remember in future: if you even think of using global then your code design needs to be improved.
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