Integrating with no variables

The following script determines the volume of a trough given f,b and L. f = width = 2, b = x = 0 (as stated in question) and L = length = 5. The script below is what I have written, but it breaks at f2

function vol = viaduct_volume_n9941835(f,b,L)
%Determines the volume of a trough with a cross sectional area defined by
% f(x) = -log(x+0.01)+exp(x). With a horizontal line segment
% g(x) = -log(0.01)+exp(0).

%Introduces functions used
f1 = @(x) -log(x+0.01)+exp(x);
f2 = @(b) -log(b+0.01)+exp(b);

%Determines intercept of two functions
fun = @(x) (-log(x+0.01)+exp(x)) - (-log(0.01)+exp(0));
Intercept = fzero(fun,f) 

%Determines definite integrals for f1 and f2
f1_int = integral(f1,0,Intercept);
f2_int = integral(f2,0,Intercept); 

%Determines Cross Sectional Area
area = f2_int - f1_int

%Determines Volume of Trough
vol = area * L

end

Answer 1

[Torsten]

If you want to integrate the constant function f2(x)=-log(b+0.01)+exp(b), just define it this way:

f2=@(x)-log(b+0.01)+exp(b)

Best wishes

Torsten.