Matrix dimensions must agree.
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This function make a coordinates from sensor in another coordintes and scale from mm to m. but it gives me the following error message (Matrix dimensions must agree.) at line: Bix = Bix .* sign(MP).* 1000;
% code
MP = [P0(:,3), P0(:,4), P0(:,5)] ./ 1000;
Bix = [(interp3 (xs, ys, zs, Bxs, abs(MP(:,1)), abs(MP(:,2)), abs(MP(:,3))));...
(interp3 (xs, ys, zs, Bys, abs(MP(:,1)), abs(MP(:,2)), abs(MP(:,3))));...
(interp3 (xs, ys, zs, Bzs, abs(MP(:,1)), abs(MP(:,2)), abs(MP(:,3))))];
Bix = Bix .* sign(MP).* 1000;
Bix = Bix .* [1, -1, -1];
댓글 수: 5
José-Luis
2017년 8월 2일
Have you tried using the debugger and looking at the size of the offending variables?
Are you trying to to implicit expansion for arithmetic operations and your Matlab < R2016b?
KSSV
2017년 8월 2일
Sizes of Bix and sign(MP) should be same.....They are not in your case.
José-Luis
2017년 8월 2일
They don't need to be the same if OP is trying to do implicit expansion.
KSSV
2017년 8월 2일
@Jose-Luis..Run this
K = rand(1,10).*rand(1,5)
You're not getting my point, I think.
Arrays no longer need to have the same number of elements for such arithmetic operations to produce results.
Unsolicited disclaimer: I am having a hard time liking that. I'll eventually get on with the times.
답변 (1개)
Jan
2017년 8월 2일
Use the debugger to identify the problem. Set a breakpoint in the failing line:
Bix = Bix .* sign(MP).* 1000;
Then run the code again until it stops. Not check the dimensions:
size(Bix)
size(MP)
For a proper elementwise multiplication, the dimensions must match. Do they?
Note that Matlab >= 2016b can auto-expand dimensions. With older versions, bsxfun helps. Perhaps you want:
Bix = bsxfun(@times, Bix, sign(MP)) * 1000;
Maybe a reshape helps here to adjust the dimensions as wanted.
카테고리
도움말 센터 및 File Exchange에서 Creating and Concatenating Matrices에 대해 자세히 알아보기
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