find element in cell

Dear all, I've problem with the cell,

a= {[67 8 33] [1 2 3 5] [2 88 5] [3 66 7 90] [3] [66 78 12 1 44 6 77 3]},

how to find each cell have number 3. answer expect it is:

b= {[1 2 3 5] [3 66 7 90] [3] [66 78 12 1 44 6 77 3]}

thanks all

Answer 1

[dbmn]

An alternative to KSSVs solution would be this one liner

b = a(cellfun(@(x) sum(x==3)>0, a));

[KSSV]

cellfun also uses loop inside...

[Jan]

The result of sum(x==3)>0 is unclear, when the cell element is the empty matrix. What about:

b = a(cellfun(@(x) any(x==3), a));

[dbmn]

Nice, using "any" there is a really neat idea.

Answer 2

[KSSV]

a= {[67 8 33] [1 2 3 5] [2 88 5] [3 66 7 90] [3] [66 78 12 1 44 6 77 3]} ;
b= {[1 2 3 5] [3 66 7 90] [3] [66 78 12 1 44 6 77 3]} ;

iwant = cell([],1) ;
count = 0 ;
for i = 1:length(a)
    if any(a{i}==3)
        count = count+1 ;
        iwant{count} = a{i} ;
    end
end
iwant