DNdog =
7
11
BNdog =
4
4
blnmynokta =
11
for i = 1:length(DNdog)
for j = 1:(length(blnmynokta))
if (BNdog(i) == blnmynokta(j))
A(i,j) = [1];
elseif (DNdog(i) == blnmynokta(j))
A(i,j) = [-1];
end
end
end
A =
0
-1 % This matrix is formed.
The matrix that should occur is;

댓글 수: 2

Jan
Jan 2017년 4월 26일
What exactly is your question?
A =
0 0 0
0 0 0
0 0 0
-1 0 0
0 -1 0
0 0 -1
I have to get this result. But I could not.

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Stephen23
Stephen23 2017년 4월 26일
편집: Stephen23 2017년 4월 26일

0 개 추천

This is simple with toeplitz:
>> nC = 3;
>> nR = 6;
>> vC = zeros(1,nC);
>> vR = zeros(1,nR);
>> vR(end-nC+1) = -1;
>> toeplitz(vR,vC)
ans =
0 0 0
0 0 0
0 0 0
-1 0 0
0 -1 0
0 0 -1

댓글 수: 3

A = zeros(nR,nC);
A(nC+1:nR+1:end) = -1;
nC = 6;
nR = 6;
If nC and nR take these values;
A =
0 0 0 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
-1 0 0 1 0 0
0 -1 0 0 1 0
0 0 -1 0 0 1 %How can I get this value?
Stephen23
Stephen23 2017년 5월 5일
@Muhendisleksi: you can solve this yourself quite easily. One way would be to use zeros and toeplitz and concatenate the outputs on top of each other. When you actually read the documentation and try some examples then you will learn how to use MATLAB and you will learn how to solve problems yourself. Start by reading the docs for the two functions that I told you, and experimenting with them.

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