Unexpected matlab expression error

function runSaliency('AloeR_SLIC.jpg')
declareGlobal;
% initialize the Image structure if necessary
if (isa('AloeR_SLIC.jpg','struct'))
img = 'AloeR_SLIC.jpg';
else
In the above code i get an error of unexpected matlab expression at line "function runSaliency('AloeR_SLIC.jpg')". The error is shown at the place where imagename is given. How should i solve this?

답변 (1개)

James Tursa
James Tursa 2017년 3월 22일
편집: James Tursa 2017년 3월 22일

0 개 추천

For function definitions, you need to have variable names for the input argument list, not explicit values. E.g., this line
function runSaliency('AloeR_SLIC.jpg')
should look something like this instead
function runSaliency(image_file_name)
where image_file_name is the name of the input variable to the function.
Then downstream in your code, this stuff
if (isa('AloeR_SLIC.jpg','struct'))
img = 'AloeR_SLIC.jpg';
should look something like this instead
if (isa(image_file_name,'struct'))
img = 'AloeR_SLIC.jpg';

댓글 수: 1

To supplement James's explanation, you specify the specific file name you want to process when you call runSaliency, not when you define runSaliency.
>> runSaliency('AloeR_SLIC.jpg')

댓글을 달려면 로그인하십시오.

카테고리

도움말 센터File Exchange에서 Programming Utilities에 대해 자세히 알아보기

질문:

2017년 3월 22일

댓글:

2017년 3월 22일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by