Can i get a DES algorithm source code in matlab?

I am trying to encrypt a message using DES encryption... I need a source code to run the program.. If anyone has it, please share the link. I tried out the following link..https://www.mathworks.com/matlabcentral/fileexchange/37847-data-encryption-standard--des- but, when i tried to run the program, it showed Error as " not enough input arguments" in the line 64 Initialization part..

댓글 수: 2

Jan
Jan 2017년 3월 16일
편집: Jan 2017년 3월 16일
@John D'Errico: Why did you close this question? I know, a simple search in the internet would reveal a link directly. But this concerns many questions.
DES encryption is not strong, such that the question does not collide with the export restrictions of the USA. Therefore this tool can be found in the FileExchange in opposite to AES.
Thank you sir.. I have already been using a DES source code, but the problem was i have to encrypt a message using a 16 bit secret key, but each and every time, it encrypts the key, instead of encrypting the message, I can't fathom why.. i applied the code [encryptt,en]=des(message,key).
my souce code of DES is as follows:
function [t C]=des( M,Key)
tic;
M = 'AF88888888555456';
%K = '1256984563214569';
K=Key;
MB=[];
for i=1:16
Mi=M(i);
MBi=['0000',dec2bin(hex2dec(Mi))];
MBi=MBi(end-3:end);
MBi=[str2num(MBi(1)),str2num(MBi(2)),str2num(MBi(3)),str2num(MBi(4))];
MB=[MB,MBi];
end
M=MB ;
KB=[];
for i=1:16
Ki=K(i);
KBi=['0000',dec2bin(hex2dec(Ki))];
KBi=KBi(end-3:end);
KBi=[str2num(KBi(1)),str2num(KBi(2)),str2num(KBi(3)),str2num(KBi(4))];
KB=[KB,KBi];
end
K=KB;
E=[32, 1, 2, 3, 4, 5; 4, 5, 6, 7, 8, 9; 8, 9,10,11,12,13; 12,13,14,15,16,17; 16,17,18,19,20,21; 20,21,22,23,24,25; 24,25,26,27,28,29; 28,29,30,31,32,1];
S1=[14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7; 0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8; 4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0; 15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13];
S2=[15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10; 3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5; 0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15; 13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9];
S3=[10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8; 13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1; 13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7; 1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12];
S4=[7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15; 13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9; 10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4; 3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14];
S5=[2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9; 14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6; 4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14; 11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3];
S6=[12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11; 10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8; 9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6; 4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13];
S7=[4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1; 13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6; 1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2; 6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12];
S8=[13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7; 1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2; 7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8; 2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11];
P=[16,7,20,21,29,12,28,17,1,15,23,26,5,18,31,10,2,8,24,14,32,27,3,9,19,13,30,6,22,11,4,25];
PC1=[57,49,41,33,25,17,9,1,58,50,42,34,26,18,10,2,59,51,43,35,27,19,11,3,60,52,44,36,63,55,47,39,31,23,15,7,62,54,46,38,30,22,14,6,61,53,45,37,29,21,13,5,28,20,12,4];
PC2=[14,17,11,24,1,5,3,28,15,6,21,10,23,19,12,4,26,8,16,7,27,20,13,2,41,52,31,37,47,55,30,40,51,45,33,48,44,49,39,56,34,53,46,42,50,36,29,32];
Ki=zeros(16,48);
K_PC1=K(PC1);
C0=K_PC1(1:28);
D0=K_PC1(29:56);
for i=1:16
if i==1||i==2||i==9||i==16
C0=[C0(2:end),C0(1)];
D0=[D0(2:end),D0(1)];
else
C0=[C0(3:end),C0(1:2)];
D0=[D0(3:end),D0(1:2)];
end
K_LS=[C0,D0];
Ki(i,:)=K_LS(PC2);
end
L=M(1:32);
R=M(33:64);
for i=1:16
E0=reshape(E',1,48);
R_E=R(E0);
R_Ki=mod(R_E+Ki(i,:),2);
B=R_Ki(1:6);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S1(x,y))];
C=C(end-3:end);
C1=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
B=R_Ki(7:12);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S2(x,y))];
C=C(end-3:end);
C2=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
B=R_Ki(13:18);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S3(x,y))];
C=C(end-3:end);
C3=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
B=R_Ki(19:24);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S4(x,y))];
C=C(end-3:end);
C4=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
tc=0.21145+0.21145;
B=R_Ki(25:30);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S5(x,y))];
C=C(end-3:end);
C5=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
B=R_Ki(31:36);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S6(x,y))];
C=C(end-3:end);
C6=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
B=R_Ki(37:42);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S7(x,y))];
C=C(end-3:end);
C7=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
B=R_Ki(43:48);
x=B(1)*2+B(6)+1;
y=B(2)*8+B(3)*4+B(4)*2+B(5)+1;
C=['0000',dec2bin(S8(x,y))];
C=C(end-3:end);
C8=[str2num(C(1)),str2num(C(2)),str2num(C(3)),str2num(C(4))];
C=[C1,C2,C3,C4,C5,C6,C7,C8];
R_P=C(P);
TEMP=L;
L=R;
R=mod(TEMP+R_P,2);
end
TEMP=L;
L=R;
R=TEMP;
C=[L,R];
CS=[];
C=num2str(C); pos=find(C~=' ');
C=C(pos);
for i=1:4:61
Ci=C(i:i+3);
CS=[CS,num2str(dec2hex(bin2dec(Ci)))];
end
C=CS;
t=tc;
end

댓글을 달려면 로그인하십시오.

답변 (0개)

카테고리

도움말 센터File Exchange에서 Programming에 대해 자세히 알아보기

태그

질문:

2017년 3월 16일

다시 열림:

2017년 3월 16일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by