points lying inside a polygon and a circle
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How can I find the number of point lies inside both a circle and a polygon (the point should lie in the mutual/overlapping area in between the circle and the polygon) ?
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Image Analyst
2017년 1월 30일
Did you try
count = 0;
if inpolygon(x,y,xCircle,yCircle) && inpolygon(x,y,xPoly,yPoly)
count = count + 1
end
where you call inpolygon twice, once passing in the circle coordinates and once passing in the polygon coordinates and then ANDing the two results together?
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KalMandy
2017년 1월 30일
Image Analyst
2017년 1월 30일
편집: Image Analyst
2017년 1월 30일
Yes, if you have the coordinates for the perimeter of the circle. If you don't, then see Matt J's formula below. You didn't specify in what form you have information about the circle. You'd put my code in a loop over all (x,y) points that you have.
count = 0;
for k = 1 : length(x)
if inpolygon(x(k),y(k),xCircle,yCircle) && inpolygon(x(k),y(k),xPoly,yPoly)
count = count + 1
end
end
Same for Matt's code - loop over all x,y that you have.
Matt J
2017년 1월 30일
Same for Matt's code - loop over all x,y that you have.
Neither approach requires a loop over x,y. INPOLYGON is vectorized.
Image Analyst
2017년 1월 30일
You're right. x and y can be a vector of coordinates. Here's a demo:
% Make circle.
x0 = 20;
y0 = 30;
R = 15;
% Plot circle
pos = [x0-R, y0-R, 2*R, 2*R];
rectangle('Position', pos, 'Curvature',[1 1]);
hold on;
% Make polygon
xv = [10, 30, 30, 10, 10];
yv = [40, 40, 5, 5, 40];
plot(xv, yv, 'b-');
grid on;
% Make 60 points for x and y
numPoints = 60;
x = 70 * rand(1, numPoints);
y = 70 * rand(1, numPoints);
plot(x, y, 'r*');
% Now count how many are in both the circle and the polygon.
count = sum(inpolygon(x,y,xv,yv) & ((x-x0).^2+(y-y0).^2<=R^2))
KalMandy
2017년 1월 30일
hanif hamden
2019년 4월 25일
If i put (x,y) in geographical coordinate and I want my radius is 10km. How should I do that?
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