How to plot this function?

(exp(-t)*(exp(-1)^floor(-t) - 1))/(exp(1) - 1)

Answer 1

[Star Strider]

It’s straightforward:

t = linspace(0, 99);

f = @(t) (exp(-t).*(exp(-floor(-t)) - 1))/(exp(1) - 1);

figure(1)
plot(t, f(t), '-pg')
grid

See the documentation for the plot function, and Function Basics (link) to understand the anonymous function.

[qpei9f dkaslfjl]

Thank you. How do I reduce the scale?

[Star Strider]

My pleasure.

You can adjust the range of ‘t’ by changing the first two arguments of the linspace function, and the number of elements in the vector it returns by specifying that in the third argument. So to set ‘t’ to be a vector of 500 elements going from -5 to +10, you would define it as:

t = linspace(-5, 10, 500);

To adjust the range of the axes in the plot, see the documentation for the axis (link) function. It will allow you to set the limits for the axes. So to set the x-axis to go from 0 to 10 and the y-axis to go from 0.5 to 0.6, after the plot call, you would set the axis limits as:

axis([0  10    0.5  0.6])

[qpei9f dkaslfjl]

Again, thanks a lot.

[Star Strider]

My pleasure.

Answer 2

[Image Analyst]

Try this:

t = linspace(-4, 15, 1000);
y = (exp(-t) .* (exp(-1) .^ floor(-t) - 1)) ./ (exp(1) - 1);
plot(t, y, 'LineWidth', 2);
grid on;
fontSize = 20;
xlabel('t', 'FontSize', fontSize);
ylabel('y', 'FontSize', fontSize);
ax = gca
ax.YAxisLocation = 'origin'
ax.XAxisLocation = 'origin'

[qpei9f dkaslfjl]

Thanks a lot. Seems it is periodic as I hoped.