I am using horizontal gridlines for a plot.
ax = gca;
ax.XGrid = 'off';
ax.YGrid = 'on';
How can I add only one vertical line through x=0?

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Star Strider
Star Strider 2017년 1월 1일

0 개 추천

You can plot a vertical line anywhere by duplicating the x-coordinate and plotting it against ylim:
figure(1)
plot([0 0], ylim, '-r')
ax = gca;
ax.XGrid = 'off';
ax.YGrid = 'on';

추가 답변 (2개)

Image Analyst
Image Analyst 2017년 1월 1일

4 개 추천

The best answer is to use YAxisLocation:
theta = linspace(-pi, pi, 800);
plot(theta, sin(theta), 'b-') % Plot something.
% Make axes go through origin instead of left and bottom sides of axes box.
ax = gca;
ax.XAxisLocation = 'origin'
ax.YAxisLocation = 'origin'

댓글 수: 4

Jan w
Jan w 2017년 1월 2일
편집: Jan w 2017년 1월 2일
Thanks! How can I put only an axis thorugh x=0 without having to move the whole YAxis? It should stay on the left side. I can't find any axis propertys: https://de.mathworks.com/help/matlab/ref/axes-properties.html Regards!
I don't understand. Normally the Y axis is at the left hand side of the axes box. If you want it to remain there, then just don't set YAxisLocation. If you want to move it so that it crosses at the x=0 line, then set YAxisLocation = 'origin'.
The only way to not move the Y axis and have it still be on the left hand side, and to have that left hand side also be the x=0 location is to set xlim to be 0:
% Get current axes limits
xl = xlim();
% Set xl(1) = 0
xl(1) = 0;
% Update the x axes limits.
xlim(xl);
Is that what you want?
Jan w
Jan w 2017년 1월 2일
Yes this works fine for me!
Image Analyst
Image Analyst 2017년 1월 2일
You're welcome. Maybe you could "Vote" for the answer (under my logo).

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the cyclist
the cyclist 2017년 1월 1일
편집: the cyclist 2017년 1월 1일

0 개 추천

line([0 0],[0 1],'Color','Black')
See line for details of setting the properties of the line.

댓글 수: 2

Brian Russell
Brian Russell 2020년 12월 16일
You simply need to write yline(0) or xline(0) for vertical and horizontal lines.
Star Strider
Star Strider 2020년 12월 17일
Note that xline and yline were introduced in R2018b, years after this was posted.

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