Automatically creating and editing Fields of struct with for Loop

That is my current code:
%%Struct Problem
for k=1:5
struct.i(k).m=rand;
struct.i(k).n=rand;
struct.i(k).o=rand;
struct.i(k).p=rand;
struct.i(k).q=rand;
end
And I want to automate the steps in a way like this:
for k=1:5
for a=['m','n','o','p','q']
struct.i(k).a=rand;
end
end
How can I automatically create and edit fields with a for loop?

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Image Analyst
Image Analyst 2016년 12월 17일
What's wrong with the first way? That's the method I'd prefer. It's much more straightforward and intuitive and easy to understand than using dynamic field names.
I really don't recommend dynamic field names, but if you insist, it is possible, though a lot more complicated than your first method:
% Initialize just one struct with 5 fields.
s = struct('m',0, 'n',0, 'o',0, 'p',0, 'q',0)
letters = {'m', 'n' 'o','p','q'}
size(s)
% Now make an array of 10 of them.
myStruct = repmat(s, 1, 10) % Whatever
size(myStruct)
for k = 1 : size(myStruct, 2)
for lIndex = 1 : length(letters)
fprintf('Assigning field %s to structure #%d\n', letters{lIndex}, k)
myStruct(k).(letters{lIndex}) = rand;
end
end

댓글 수: 3

thank you very much! That helped a lot :) I have one more question: I have created the struct the way you propose. Now I want to extract the 4th up to the 6th row and save it into a new struct with the same fields. How do I do that?
Try this:
newStruct = myStruct(4:6);
thank you very much :)

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