필터 지우기
필터 지우기

Morton scanning ?

조회 수: 3 (최근 30일)
vishnu
vishnu 2012년 3월 9일
마감: Walter Roberson 2017년 1월 3일
i am long days itslef looking for morton scanning . but i do not suceed to create morton matrix for an image ...
here is some code for 4*4 which i referred ..
clc;
clear all;
close all ;
n=2;
ind=morton(n);
a=reshape(1:4^n,2^n,2^n);
disp(a)here is the matlab function
function ind=morton(n);
% MORTON(N) return the morton permutation order for array of size 2^N
% e.g.
% n=2;
% matrix size is 2^n
% ind=morton(n);
% d=fix(rand(2^n,2^n)*10);
% disp(d)
% disp(d(ind))
linind4=(1:4^n)-1; %start index count for array at zero
ind4str=dec2base(linind4,4); %convert indices to base-4
b1=dec2bin(str2num(ind4str(:,1))); %split each base-4 into two base-2numbers
b2=dec2bin(str2num(ind4str(:,2)));
rb=[b1(:,1) b2(:,1)]; %the rows are given by the first bits of b1 and
b2
cb=[b1(:,2) b2(:,2)]; %the columns are given by the second bits of b1 and b2
r=bin2dec(rb)+1; %convert the row from bit to decimal
c=bin2dec(cb)+1; %convert column
ind=[2^n*(c-1)+r]'; %make a linear row index into array for easyaddressing
%morton.m ends
if any one knows how to create for a image please help me
  댓글 수: 5
vishnu
vishnu 2012년 3월 15일
its an urgent work please
Walter Roberson
Walter Roberson 2012년 3월 20일
http://www.mathworks.com/matlabcentral/answers/29922-why-your-question-is-not-urgent-or-an-emergency

댓글을 달려면 로그인하십시오.

답변 (0개)

이 질문은 마감되었습니다.

카테고리

Help CenterFile Exchange에서 Introduction to Installation and Licensing에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by