error in std for 3d matrix

Hey guys!

I am trying to find the std of a 3D matrix, where size(X) is 207 x 201 x 34. Since I must reshape to find std, I am using this formula: std(reshape(X,1,207*201*34)).

And I obtain this error: Error in std (line 31) y = sqrt(var(varargin{:}));

When I look at the syntax, I thought of using std(reshape(X,1,207*201*34), 0, 3), where 3 is for 3D, however I still obtain the same error.

What I am missing?

Thank you very much in advance!

[Steven Lord]

What is the full text of the error message (including everything printed in red?)

[Anastasia]

Hello, this is the full text of the error message:

Error using var (line 58) First argument must be single or double.

Error in std (line 31) y = sqrt(var(varargin{:}));

Error in Code3D (line 27) th=mean(mean(mean(X))) + std(reshape(X,1,207*201*34));

Is the problem that X is nor single nor double, but 207*201*34? How can I fix that?

Thank you!

Answer 1

[Isabella Osetinsky-Tzidaki]

try std(x(:))

[Anastasia]

Hello! Thank you for your answer but I obtain the same error...

Answer 2

[Guillaume]

Error: First argument must be single or double

Well, clearly, your first argument (a transform of X) is not single or double. So what is:

class(X)

If it's an integer type:

Xdouble = double(X);
th = mean(Xdouble(:)) + std(Xdouble(:));

[Anastasia]

The class is uint16. I tried it and it works, is it correct to use the code you gave me with a uint16 class?

Thanks!

[Guillaume]

Without context it's impossible to say if it's correct or not. Certainly, if you want the standard deviation of your integers, you have to convert them to double. If an integer result is then required, you can convert the output back to uint16 (with the loss of precision that it entails).