Frequency Response Function and FFT for Modal Analysis

조회 수: 67 (최근 30일)
R SW
R SW 2016년 12월 12일
답변: Mathieu NOE 2024년 12월 10일 11:00
I am experimentally testing a material to retrieve its natural frequencies through modal analysis. The type of testing is based around impulse response. My sampling frequency was 10kHz. My acccelerometer's sensisitivty was 100mV/g and my impact hammer's sensitivity was 2.25mV/N. My aim is to obtain an accurate FRF graph. My entire code:
%reading excel file
dataset = xlsread('BrassFRF.xlsx','Sheet1','A1:C50000');
%%Creating and filling data variables
a=dataset(:,2);
n=dataset(:,3);
%%Converting acceleraltion voltages into acceleration (mm/sec^2)
a=a.*((1/0.1)*9.81);
%%Converting force voltages into Newton (N)
n=n.*(1/0.00225);
%%Creating FFT using acceleration
L=length(a);
NFFT=2.^nextpow2(L);
V=fft(a,NFFT)/L;
Fs=10000;
freq=Fs/2*linspace(0,1,NFFT/2+1);
subplot(3,1,1)
plot(freq,2*abs(V(1:NFFT/2+1)))
xlabel('Frequency (Hz)');
title('Velocity FFT ')
%%Creating FFT for using force
F=fft(n,NFFT)/L;
subplot(3,1,2)
plot(freq,2*abs(F(1:NFFT/2+1)))
xlabel('Frequency (Hz)');
title('Impulse FFT ')
%%FRF
FRF=V./F;
subplot(3,1,3)
plot(abs(FRF))
xlabel('Frequency (Hz)');
title('FRF')
Please tell me if you find any errors that can be the cause of an incorrect FRF. My suspect is the impulse FFT.
  댓글 수: 1
Lingyuan Kong
Lingyuan Kong 2021년 1월 22일
The last section is wrong, it should be:
FRF=V./F;
subplot(3,1,3)
plot(freq, abs(FRF(1:NFFT/2+1)))
xlabel('Frequency (Hz)');
title('FRF')

댓글을 달려면 로그인하십시오.

답변 (4개)

durukan dilek
durukan dilek 2017년 11월 1일
편집: durukan dilek 2017년 11월 1일
did you obtain frf of acceleration/force? why did you write V/F? why did you use velocity?
L=length(a); NFFT=2.^nextpow2(L); V=fft(a,NFFT)/L; Fs=10000; freq=Fs/2*linspace(0,1,NFFT/2+1); subplot(3,1,1) plot(freq,2*abs(V(1:NFFT/2+1))) xlabel('Frequency (Hz)'); title('Velocity FFT ') set(gca, 'YScale','log')

Deniz Kny
Deniz Kny 2019년 3월 6일
how did you know your sampling frequency was 10khz? I have a accelerometer data and, trying to obtain fft like you. i need a Fs but i dont know how can i get this info.
  댓글 수: 1
imthiyas manarikkal
imthiyas manarikkal 2019년 11월 8일
You can actually check your resonance frequency or natural frequency. The sampling frequency must be twice of your natural frequency (Nyquiste Theorem)

댓글을 달려면 로그인하십시오.


Jose Ordaz
Jose Ordaz 2019년 12월 19일
Hello,
i'm working in the same way, trying to obtain the natural frequency and damping of some materiales using the information from a hammer and a accelerometer. Can you please help me with this?, how you solve your problem with the FRF?.
thanks

Mathieu NOE
Mathieu NOE 2024년 12월 10일 11:00
hello
yes I a coming very late in the show but maybe there is still a need for a better code
you can improve the FRF estimation if you have multiple hits in the same record - with enough time in between hits to let the response decay to zero - see my other answer here : How can I obtain accurate and high-quality FRF results? - MATLAB Answers - MATLAB Central
results :
T = Mode Frequency Damping
____ _________ _________
1 1845.7 0.0072161
2 2336.8 0.0060413
3 2895.7 0.0080089
4 3515.7 0.0070846
code :
%% Load data
dataset = xlsread('BrassFRF.xls','Sheet1','A1:C50000');
%%Creating and filling data variables
accel_signal=dataset(:,2);
force_signal=dataset(:,3);
%%Converting acceleraltion voltages into acceleration (mm/sec^2)
accel_signal=accel_signal.*((1/0.1)*9.81);
accel_unit = 'mm/sec^2';
%%Converting force voltages into Newton (N)
force_signal=force_signal.*(1/0.00225);
force_unit = 'N';
%% Extract force and acceleration data
time = dataset(:, 1);
dt = mean(diff(time));
Fs = 1/dt;
samples = numel(force_signal);
channels = size(accel_signal, 2);
time = (0:samples-1)*dt; % we need to re-create the time signal
%% FFT processing parameters
nfft = 1024*2;
% Trigger the data (using "zero crossing" on the force signal)
pre_trig_duration = 10e-3; % (seconds) - add some time to shift the pulse signal to the right
force_signal_level = 0.5*max(force_signal);
[Zx] = find_zc(time, force_signal, force_signal_level);
Zx = Zx - pre_trig_duration;
% Recommended max nfft
if numel(Zx) > 1
recommended_max_nfft = floor(min(Fs * diff(Zx)));
else
recommended_max_nfft = numel(time);
end
%% Check valid segments (duration in samples must be above nfft)
pd = [Fs * diff(Zx); samples - Fs * Zx(end)]; % Pulse durations in samples
data_valid = find(pd >= nfft);
figure(1),
subplot(2,1,1), plot(time, force_signal)
title('Force Signal (raw)');
xlabel('Time (s)');
ylabel(force_unit);
if nfft > recommended_max_nfft
text(max(time) * 0.1, max(force_signal) * 0.9, ...
['Selected nfft = ' num2str(nfft) ' is above recommended max value : ' num2str(recommended_max_nfft)]);
end
subplot(2,1,2), plot(time, accel_signal)
title('Acceleration Signal (raw)');
xlabel('Time (s)');
ylabel(accel_unit);
%% FFT Processing - Combined Section
windowx = ones(nfft, 1); % No window on force signal (default)
% windowx(round(0.2*nfft:end)) = 0 ; % "force" window on force signal ( window = 1 during first 20% of time, then 0)
% windowx(round(0.1*nfft:end)) = 0 ; % "force" window on force signal ( window = 1 during first 10% of time, then 0)
windowy = ones(nfft, 1); % No window on acceleration signal
% windowy = exp(-2.3*(0:nfft-1)/nfft)'; % 0.1 exp window on response sensor signal
% windowy = exp(-4.6*(0:nfft-1)/nfft)'; % 0.01 exp window on response sensor signal
Pxx = zeros(nfft, 1);
Pxy = zeros(nfft, channels);
Pyy = zeros(nfft, channels);
% Check if data_valid is not empty
if isempty(data_valid)
error('No data or nfft too large - check data & nfft settings');
else
for ck = 1:numel(data_valid)
k = data_valid(ck);
% Select time data
ind_start = find(time >= Zx(k), 1, 'first');
ind = (ind_start : ind_start + nfft - 1);
time_measure = time(ind);
time_measure = time_measure - time_measure(1);
force_signal_measure = force_signal(ind);
accel_signal_measure = accel_signal(ind);
figure(2), % just to show the individual gaussian pulses with different time offsets
subplot(2,1,1),plot(time_measure, windowx.*force_signal_measure)
xlabel('Time (s)');
ylabel(force_unit);
hold on
subplot(2,1,2),plot(time_measure,(windowy*ones(1,channels)).*accel_signal_measure)
xlabel('Time (s)');
ylabel(accel_unit);
hold on
leg_str1{ck} = ['hit # ' num2str(k)];
leg_str2{ck} = ['record # ' num2str(k)];
% FFT processing
x = force_signal_measure;
y = accel_signal_measure;
xw = windowx .* x;
yw = (windowy * ones(1, channels)) .* y;
Xx = fft(xw, nfft);
Yy = fft(yw, nfft, 1);
Xx2 = abs(Xx).^2;
Xy2 = Yy .* (conj(Xx) * ones(1, channels));
Yy2 = abs(Yy).^2;
Pxx = Pxx + Xx2;
Pxy = Pxy + Xy2;
Pyy = Pyy + Yy2;
end
subplot(2,1,1),legend(leg_str1); % add legend of valid data
subplot(2,1,2),legend(leg_str2); % add legend of valid data
% Select first half
if ~any(any(imag([x y]) ~= 0)) % If x and y are not complex
if rem(nfft, 2) % nfft odd
select = [1 : (nfft + 1) / 2];
else
select = [1 : nfft / 2 + 1]; % Include DC AND Nyquist
end
Pxx = Pxx(select);
Pxy = Pxy(select, :);
Pyy = Pyy(select, :);
else
select = 1:nfft;
end
% Set up output parameters
Txy = Pxy ./ (Pxx * ones(1, channels)); % Transfer function estimate
Cxy = (abs(Pxy).^2) ./ ((Pxx * ones(1, channels)) .* Pyy); % Coherence function estimate
f = (select - 1)' * Fs / nfft;
end
%% Plot FRF and Coherence
flow = 10;
fhigh = Fs / 2.56;
%% Modal Analysis (Natural Frequencies and Damping Ratios)
N = 4; % Number of dominant modes to identify
% Only use valid data (coherence above 0.9)
ind = Cxy > 0.9;
FR = [flow fhigh];
[fn, dr] = modalfit(Txy(ind), f(ind), Fs, N, 'FitMethod', 'pp', 'FreqRange', FR);
T = table((1:N)', fn, dr, 'VariableNames', {'Mode', 'Frequency', 'Damping'});
%%
figure(3)
subplot(3, 1, 1), semilogy(f, abs(Txy), 'r',fn,interp1(f,abs(Txy),fn),'db');
title(['FRF Estimation based on Valid Data Chunks']);
xlim([flow fhigh]);
ylabel(['Magnitude (' accel_unit ' / ' force_unit ')']);
subplot(3, 1, 2), plot(f, 180/pi * (angle(Txy)), 'r');
xlim([flow fhigh]);
ylabel('Phase (°)');
subplot(3, 1, 3), plot(f, Cxy, 'r');
xlim([flow fhigh]);
xlabel('Frequency (Hz)');
ylabel('Coherence');
ylim([0 1.1]);
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function [Zx] = find_zc(x,y,threshold)
% find time values of positive slope zero (or "threshold" value ) y
% crossing points
% put data in rows
x = x(:);
y = y(:);
% positive slope "zero" crossing detection, using linear interpolation
y = y - threshold;
zci = @(data) find(diff(sign(data))>0); %define function: returns indices of +ZCs
ix=zci(y); %find indices of + zero crossings of x
ZeroX = @(x0,y0,x1,y1) x0 - (y0.*(x0 - x1))./(y0 - y1); % Interpolated x value for Zero-Crossing
Zx = ZeroX(x(ix),y(ix),x(ix+1),y(ix+1));
end

카테고리

Help CenterFile Exchange에서 Multirate Signal Processing에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by