Alternate for flipr command in matlab

Hi,

m = 3; n = 8; There are 8 elements in A

A = [33,47,44,49,40,21,45,48];

After sorting in descending order

A = [49,48,47,45,44,40,33,21]

I need final matrix

final =[ 49 48 47 ; 40 44 45 ; 33 21 ]

In first two rows 3 elemets has to be there.

In third row 2 elements has to be there,because n = 8.

Second row is printed in reverse order.

I cant use "flipr" in this case bcoz matrix is not same size.

Alternate rows has to be printed in reverse order.

Advice me regarding this.

Answer 1

[Walter Roberson]

You cannot create a numeric matrix which has different number of elements in various rows or columns. 8 elements cannot be arranged in to a 3-row numeric matrix -- not without adding an extra element.

[Andrei Bobrov]

Hi Walter! I agree with you.

Answer 2

[Andrei Bobrov]

A = [33,47,44,49,40,21,45,48];
m = 3;
n = numel(A);
out = nan(m,ceil(n/m));
out(1:n) = sort(A,'descend');
out(:,2:2:end) =  out(end:-1:1,2:2:end);
out = out'

[Bathrinath]

Thanks andrei bobrov,your code works