Get several subsets from a set using two arrays.

Hello.

For example.

I have the following set:

exSet = 21:40;

And 2 arrays, one with the indexes of the lower position and the second with the indexes of the higher position.

Lower position array:

lPos = [2 8];

Upper position array:

uPos = [11 16];

The resulting subsets are:

subSet1 = extSet(lPos(1) : uPos(1)) = 22:31;
subSet2 = extSet(lPos(2) : uPos(2)) = 28:36;

But, I want to do this in a single step because both my set exSet and the arrays have much more elements.

To avoid a for loop, I will appreciate suggestions.

Best Regards,

[Massimo Zanetti]

What do you mean by "in a single step"?

[Tiago Marçal]

Well, it is more like an efficient path to solve the problem instead of using a loop.

Of course, if there isn't a solution to solve the problem in a single step, or in just one code line, i will be thankful if you give me the best solution you know.

Answer 1

[Massimo Zanetti]

Ok, I got it. You can work like this, by exploiting arrayfun, which iterates an operation on array elements.

vect = 101:120;
s(1).lim=[11,15];
s(2).lim=[4,9];
s(3).lim=[9,18];

ext = arrayfun( @(x) vect(x.lim(1):x.lim(2)) , s , 'UniformOutput' , false);

ext{1}
ext{2}
ext{3}

As you can see, in just one call, it is possible to extact from vect as many sub-vectors as we want. :)

Answer 2

[Tiago Marçal]

It works.

Thanks.