Tight Boundary around a Set of Points

조회 수: 15 (최근 30일)
Jason Nicholson
Jason Nicholson 2016년 8월 16일
편집: Jason Nicholson 2018년 1월 4일
I want to draw a tight boundary around a set of points. The code is used below to draw the black boundary around the blue points. The red areas show areas that are not tight enough for my application. Does anyone have a suggestion on how to get a tighter boundary? The data is attached.
clc; clear; close all;
load('xy.mat')
xy = [x y];
plot(xy(:,1), xy(:,2),'.')
grid on;
hold all;
xyNormalized = xy;
for iColumn = 1:2
minValue = min(xy(:,iColumn));
maxValue = max(xy(:,iColumn));
xyNormalized(:,iColumn) = (xy(:,iColumn)-minValue)/(maxValue - minValue);
end
k = boundary(xyNormalized,1);
xyBoundary = xy(k,:);
h = plot(xyBoundary(:,1), xyBoundary(:,2),'k');

채택된 답변

Thorsten
Thorsten 2016년 8월 16일
편집: Thorsten 2016년 8월 17일
[ux, ia, ib] = uniquetol(x, 0.01);
for i= 1:max(ib), M(i,:) = [min(y(ib == i)) max(y(ib == i))]; end
plot(x, y, '.')
hold on
plot(ux, M(:,1), 'r-')
plot(ux, M(:,2), 'r-')
This is how it looks like
  댓글 수: 2
Jason Nicholson
Jason Nicholson 2016년 8월 17일
편집: Jason Nicholson 2016년 8월 17일
Good answer. It works. I did have to tighten the tolerance to 0.001.
clc; clear; close all;
load('xy.mat')
xy = [x y];
plot(xy(:,1), xy(:,2),'.')
grid on;
hold all;
[ux, ia, ib] = uniquetol(x, 0.001);
for i= 1:max(ib)
M(i,:) = [min(y(ib == i)) max(y(ib == i))];
end
plot(ux, M(:,1), 'r-')
plot(ux, M(:,2), 'r-')
Thorsten
Thorsten 2016년 8월 17일
You're welcome. Please accept my answer if it works for you.

댓글을 달려면 로그인하십시오.

추가 답변 (2개)

FirefoxMetzger
FirefoxMetzger 2016년 8월 16일
This draws a boundary along the highest elements of each class, the lowest elements of each class and has the left and right outer classes as boundary:
load('xy.mat')
xy = [x y];
plot(xy(:,1), xy(:,2),'.')
grid on;
hold all;
%split data into classes and find max/min for each class
class_label = unique(x);
upper_boundary = zeros(size(class_label));
lower_boundary = zeros(size(class_label));
for idx = 1:numel(class_label)
class = y(x == class_label(idx));
upper_boundary(idx) = max(class);
lower_boundary(idx) = min(class);
end
% plot a nice boundary in red
left_boundary = y(x == class_label(1));
right_boundary = y(x == class_label(end));
plot(class_label(1)*ones(size(left_boundary)),left_boundary,'r')
plot(class_label,upper_boundary,'r')
plot(class_label(end)*ones(size(right_boundary)),right_boundary,'r')
plot(class_label,lower_boundary,'r')
  댓글 수: 3
Sinvaldo Moreno
Sinvaldo Moreno 2017년 12월 24일
I believe the fast and easy way is get the boundaries:
% code
load('xy.mat');
xy = [x y]
[k, v] = boundary(xy(:,1),xy(:,2));
plot(xy(:,1), xy(:,2),'.');
hold on;
plot(xy(k,1),xy(k,2));
Jason Nicholson
Jason Nicholson 2018년 1월 4일
편집: Jason Nicholson 2018년 1월 4일
Sinvaldo. This is not correct. I want a tight boundary.
The boundary command has an input s called the "shrink factor." A shrink factor of 0 corresponds to the convex hull of the points. A shrink factor of 1 corresponds to the tightest signel region boundary the points. By default, the shrink factor is 0.5 when it is not specified in the boundary command. For example, your code yields the following graph. Look at the answer that I accepted and you will see that the boundary is tighter than the boundary in the graph below.
Even if the shrink factor is set to 1 like in the code and picture below, I still don't think the boundary is tight enough for my purposes. Thanks for the answer but it just isn't what I am looking for.
[k, v] = boundary(xy(:,1),xy(:,2),1);

댓글을 달려면 로그인하십시오.


Image Analyst
Image Analyst 2016년 8월 16일
You might try the envelope function in the Signal Processing Toolbox:
  댓글 수: 1
Jason Nicholson
Jason Nicholson 2016년 8월 17일
Interesting idea. However, the envelope function needs the input to output to be single valued. In math this is called a function, f(x). i.e. There cannot be multiple y values for a single x value.

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Bounding Regions에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by