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Please Speed UP This Algoritm!!!

조회 수: 1 (최근 30일)
Paolo Rossi
Paolo Rossi 2012년 2월 13일
편집: Cedric 2013년 10월 10일
hi i'd like to know if there's is a way to speed up this algoritm where:, lphi is a vector of 120 elements, IN4 is a matrix of 4x8192, aaa is a 3D matrix of 4x8192x120
for k = 1:lphi;
B4(k,:) = sum(IN4.*aaa(:,:,k));
end
B = sum(abs(B4).^2,2);
thanks, i don't know if in c++ it work faster any ideas?
  댓글 수: 2
the cyclist
the cyclist 2012년 2월 13일
It's not clear to me what your loop does. You say that lphi is a vector, but then you loop over k=1:lphi. That seems odd to me, and not really what you want.
Paolo Rossi
Paolo Rossi 2012년 2월 13일
Sorry, lphi is not a vector is the length of a vector lphi = 120

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채택된 답변

Jonathan Sullivan
Jonathan Sullivan 2012년 2월 13일
B4 = reshape(permute(bsxfun(@tims,IN4,aaa),[3 1 2]),size(aaa,3),[]);
B = sum(abs(B4).^2,2);
  댓글 수: 4
Sean de Wolski
Sean de Wolski 2012년 2월 13일
And it still doesn't give the correct results.
Sean de Wolski
Sean de Wolski 2012년 2월 13일
Like, I said, this does not produce correct results, nor does it work as written. PERMUTEing a big array will likely never be faster than a well written for-loop.

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추가 답변 (2개)

Sean de Wolski
Sean de Wolski 2012년 2월 13일
bsxfun is lurking (update: and staying hidden)!
The fastest I could get it was to dynamically preallocate your for-loop.
for k = 120:-1:1
B5(k,:) = sum(IN4.*aaa(:,:,k));
end
B2 = sum(abs(B5).^2,2);
  댓글 수: 1
Paolo Rossi
Paolo Rossi 2012년 2월 13일
i will study this function

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James Tursa
James Tursa 2012년 2월 13일
Another option you can try using some FEX submissions (slightly better at memory management than your original code):
uninit; % One time only, to built the mex routine
mtimesx; % One time only, to build the mex routine
B4 = uninit(8192,1,lphi); % Fast create variable
for k = 1:lphi;
B4(:,:,k) = sum(IN4.*aaa(:,:,k)).'; % Contiguous result
end
B = mtimesx(B4,'t',B4,'speedomp'); % Fast nD dot product
B = B(:); % Reshape result to column
You can find uninit and mtimesx here:
Note: This won't give exactly the same answer as the MATLAB code because the last dot product operation is done internally in mtimesx differently from MATLAB.
Q: Is everything real? What is the point of the abs( )?
  댓글 수: 3
James Tursa
James Tursa 2012년 2월 13일
In that case use 'c' instead of 't' in the mtimesx call. E.g.,
B = mtimesx(B4,'c',B4,'speedomp');
Paolo Rossi
Paolo Rossi 2012년 2월 13일
Thanks but the bottle neck is in the loop, infact the loop takes 0.1 sec...may be this is the best performance, i will try anyway your functions

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